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mestny [16]
3 years ago
6

ASAP NEED HELP ON MY MATH RETAKE I NEED HELP PLZZZ IM BEGGING YALL

Mathematics
1 answer:
Sindrei [870]3 years ago
8 0

Answer:

B) There tends to be a linear association between variables

c) the data includes one or more outliers

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A 26' long painting is how many yards?
guapka [62]
It's <span>0.72 yards.
1 = 0.02
so 26*0.02=0.72</span>
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4 years ago
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Can someone please help me I really need help help me thank you
harkovskaia [24]

Answer:

<h2><em><u>A to C = 25 </u></em></h2><h2><em><u>A to B = 13 </u></em></h2><h2><em><u>C to B = 37 </u></em></h2><h2><em><u></u></em></h2>

Step-by-Step Explanation:

<em><u>Perimeter</u></em> = 75

<em><u>Sides:</u></em>

2x + 3

3x + 4

2x - 9

<h2 /><h2><em><u>1. Equal the sides added together to the perimeter</u></em></h2>

75 = 2x + 3 + 3x + 4 + 2x - 9

<h2><em><u>2. Simplify Like terms</u></em></h2>

2x + 3 + 3x + 4 + 2x - 9  = 7x - 2

<h2><em><u>3. Place the equation back together</u></em></h2>

75 = 7x - 2

<h2><em><u>4. Isolate the variables and numbers</u></em></h2>

75 = 7x - 2

+2        +2

77 = 7x

<h2><em><u>5. Simplify the equation</u></em></h2>

77 = 7x

/7     /7

<h2><em><u>11 = x </u></em></h2>

<h2><em><u>6. Substitute the value of x into the side lengths.</u></em></h2>

2x + 3 = 2(11) + 3 = 22 + 3 = <em><u>25</u></em>

3x + 4 = 3(11) + 4 = 33 + 4 = <em><u>37</u></em>

2x - 9 = 2(11) - 9 = 22 - 9 = <em><u>13</u></em>

5 0
3 years ago
What is 25,000,000 x 25,0000 = what
romanna [79]

Answer: 6.25^12

Step-by-step explanation:

5 0
4 years ago
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Can someone help me please?
Rashid [163]
Idk your best bet is to look it up online thats what i do often
8 0
3 years ago
Let U = {a, b, c, e, d, e, f, g, h, i, j, k}; A = {a, b, e, f, h, j}; B = {b, c, d, f, j}. Draw a Venn Diagram with a rectangle
marishachu [46]
<h3>Answer: Venn Diagram is below</h3>

The rectangle represents the universal set (marked as "set U"). Everything is contained in this rectangle.

Circle A represents set A = {a, b, e, f, h, j}

Circle B represents set B = {b, c, d, f, j}

The common elements between the two sets are {b, f, j}, so we'll write these three values in the overlapping portion of the two circles.

The items {a,e,h} will go in circle A, but not in the overlapping portion since they are found only in set A.

Similarly we'll have {c,d} go in circle B but not in the overlapping portion since these items are only found in set B.

The remaining terms {g, i, k} go outside both circles, but inside the rectangle, because neither of these elements are in set A or set B.

6 0
3 years ago
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