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3 years ago

Please help someone..

Mathematics

2 answers:

slamgirl [31]3 years ago

6 0

Answer:

x=(3e+2d)/(2g-ef)

Step-by-step explanation:

d=e(3+fx)/(2+gx)

or, 2d+2gx=3e+efx

or, 2gx-efx=3e+2d

or, x(2g-ef)=3e+2d

or, x=(3e+2d)/(2g-ef)

Semmy [17]3 years ago

5 0

Answer:

x = (-2d + 3e) / (dg - fe)

Step-by-step explanation:

We solve it by using algebra.

1. Multiply each side by 2 + gx:

dgx + 2d = fxe + 3e

2. Subtract fxe on both sides:

dgx − fxe + 2d = 3e

3. Subtract 2d from both sides:

dgx − fxe = −2d + 3e

4. Factor out x:

x (dg − fe) = −2d + 3e

5. Divide dg - fe:

x = (-2d + 3e) / (dg - fe)

I hope this helped! :D

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o-na [289]

Answer:

The parabola is translated down 2 units.

Step-by-step explanation:

You have the parabola f(x) = 2x² – 5x + 3

To change this parabola to f(x) = 2x² - 5x + 1, you must have performed the following calculation:

f(x) = 2x² – 5x + 3 -2= 2x² - 5x + 1 Expresion A

The algebraic expression of the parabola that results from translating the parabola f (x) = ax² horizontally and vertically is g (x) = a(x - p)² + q, translating in the same way as the function.

If p> 0 and q> 0, the parabola shifts p units to the right and q units up.
If p> 0 and q <0, the parabola shifts p units to the right and q units down.
If p <0 and q> 0, the parabola shifts p units to the left and q units up.
If p <0 and q <0, the parabola shifts p units to the left and q units down.

In the expression A it can be observed then that q = -2 and is less than 0. So the displacement is down 2 units.

This can also be seen graphically, in the attached image, where the red parabola corresponds to the function f(x) = 2x² – 5x + 3 and the blue one to the parabola f(x) = 2x² – 5x + 1.

In conclusion, the parabola is translated down 2 units.

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