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2 years ago

What is the surface area of a rectangular prism that has these dimensions? 14m x 8m x 6m

1 answer:

4 0

The surface area is 488m2:)

(keep in mind every side has an opposite...)

14 x 8 x 2 = 224

14 x 6 x 2 = 168

6 x 8 x 2 = 96

224 + 168 + 96 = 488

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Simplify 8 . 3 . X<br> A.13x<br> B.24x<br> C.22x<br> D.48x

olchik [2.2K]

Answer:

D. 48x

Step-by-step explanation:

sana nakatulong

6 0

2 years ago

Geometry- I need an answer for x and y.

elixir [45]

Answer:

x = 13sqrt(3) ft = 22.5 ft

y = 13 ft

Step-by-step explanation:

The triangle is a 30-60-90 right triangle.

The ratio of the lengths of the sides is

short leg : long leg : hypotenuse = 1 : sqrt(3) : 2

From the ratio above we see that the hypotenuse is twice the short leg.

The long leg is sqrt(3) times the short leg.

y = short leg

x = long leg

26 ft = hypotenuse

y = 26 ft/2 = 13 ft

x = 13 ft * sqrt(3) = 13sqrt(3) ft = 22.5 ft

6 0

2 years ago

Read 2 more answers

Please help!! MathsWatch, Surd Expressions, Clip 207c

dexar [7]

Answer:

$A=(72+36\sqrt{3})\ mm^2$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

$b=AB+BC+CD+DE$ ----> by segment addition postulate

substitute

$b=3+3+3+3=12\ mm$

step 2

Find the height of rectangle

$a=FB+CG+GH$ ---> by segment addition postulate

substitute the given values

$a=3+CG+3\\a=6+CG$

Find the length sides CG

Applying the Pythagorean Theorem

$BG^2=BC^2+CG^2$

substitute the given values

$6^2=3^2+CG^2$

$CG^2=6^2-3^2$

$CG=\sqrt{27}\ mm$

simplify

$CG=3\sqrt{3}\ mm$

therefore

$a=(6+3\sqrt{3})\ mm$

step 3

Find the area of rectangle

$A=ab$

we have

$a=(6+3\sqrt{3})\ mm$

$b=12\ mm$

substitute

$A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2$

8 0

2 years ago

ANSWER PLS URGENT VERY URGENT TYSM ik its a lot of questions but id really really be grateful for the help

anyanavicka [17]

Step-by-step explanation:

about circle R

arc angle MP = angle MRP = 78°

angle M = angle LMP.

according to the rules of inscribed angles, LMP is half of angle LRP.

LRP + MRP = 180° because together they cover the whole LM segment (half-circle).

LRP = 180 - MRP = 180 - 78 = 102°

so, LMP = angle M = 102/2 = 61°

also circle R (with arc ULNP)

the arc ULNP = arc UL + arc LN + arc NP = 160°

due to the congruent definition of JU and MP we know that arc UL = arc NP.

and we know arc LN = arc JM = 18°.

so,

160 = 2×arc NP + 18

142 = 2×arc NP

arc NP = 71° = arc UL

now, because arc MP + arc LP = 180 (half-circle),

arc MP = 180 - arc LP = 180 - arc LN - arc NP =

= 180 - 18 - 71 = 91°

about the circle R with 2 congruent chords :

the second answer : they are equidistant from R (the center of the circle).

about circle W

arc MK + arc KL = 180° (half-circle).

and we see

arc HL = arc KL = 53°.

so,

arc MK + 53 = 180°

arc MK = 180 - 53 = 127°

about circle M

arc QTS = 204°.

therefore, arc QRS = 360 - arc QTS = 360 - 204 =

= 156° = angle QMS.

according to the rules of inscribed angles

angle QTS = QMS/2 = 156/2 = 78°

4 0

1 year ago

Write and graph an equation in point slope form of the line that passes through the given point and with the given slope (3,4) m

AnnyKZ [126]

So slope intercept form y=mx+b slope is m

m=6 so
y=6x+b
this is not the legit way but it works so
put in 3 for x and 4 for y and solve for b
4=6(3)+b
4=18+b
-14=b
b=-14

the slope intercep form is y=6x-14

4 0

3 years ago