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Thepotemich [5.8K]
3 years ago
7

Which numbers belong to the range of the revolution {(4,-1),(-7,2),(1,2),(2,1)}

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0
1.
The range are y's. The y's in {(4,-1),(-7,2),(1,2),(2,1)} are -1,1,2 ⇒ A,B,C

2.
The domain are x's. The x's in {(4,-1),(-7,2),(1,2),(2,1)} are -7,1,2,4 ⇒ A,B,D

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.help me solve please and thank you✨
svetlana [45]
The first one, SAS Postulate
8 0
3 years ago
Which exponential function is represented by the values in the table?
svlad2 [7]

Here we use the equation

y = a(b)^x

Taking points (0,4), (1,2)

Substituting the point (0,4) , we will get

4 = a(b)^0
\\
4 = a(1)  \\
a =4

Substituting (1,2) we will get

2 = 4 (b)^1
\\
2/4 = b
\\
b = 1/2

So we have

a = 4, b = 1/2

Therefore , required equation is

y = 4(1/2)^x

7 0
3 years ago
Read 2 more answers
You have 42,784 grams of a radioactive kind of curium. If its half-life is 18 years, how much will be left after 72 years?
s344n2d4d5 [400]

Answer:

2,674.14 g

Step-by-step explanation:

Recall that the formula for radioactive decay is

N = N₀ e^(-λt)

where,

N is the amount left at time t

N₀ is the initial amount when t=0, (given as 42,784 g)

λ = coefficient of radioactive decay

  = 0.693 ÷ Half Life

  = 0.693 ÷ 18

  = 0.0385

t = time elapsed (given as 72 years)

e = exponential constant ( approx 2.7183)

If we substitute these into our equation:

N = N₀ e^(-λt)

= (42,787) (2.7183)^[(-0.0385)(72)]

= (42,787) (2.7183)^(-2.7726)

=  (42,787) (0.0625)

= 2,674.14 g

6 0
3 years ago
Guys can you help me and my brother with these 2 questions (im confused on this).
leonid [27]

Answer:

1, i can't see the pic so i can't answer the Question

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Tan 12 degrees = 10/x
Ilia_Sergeevich [38]
Solve like an equation,
You need x by itself.
Since x is on the denominator, multiply both sides by x to clear the fraction.
Tan 12 = 10/x
x Tan12 = 10
Divide both sides by Tan12
x = 10/(Tan12)
x = 47
7 0
3 years ago
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