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Nadusha1986 [10]
3 years ago
8

The cross-sectional areas of a right pyramid and a right cylinder are congruent. The right pyramid has a height of 10 units, and

the right cylinder has a height of 7 units. Which conclusion can be made from the given information?
Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

The volume of the cylinder is 2.1 times the volume of the pyramid

Step-by-step explanation:

step 1

Find the volume of the pyramid

we know that

The volume of a right pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the base of pyramid

H is the height of the pyramid

we have

H=10\ units

substitute

Vp=\frac{10}{3}B\ units^{3}

step 2

Find the volume of the right cylinder

we know that

The volume of right cylinder is equal to

V=BH

where

B is the area of the base of cylinder

H is the height of the cylinder

we have

H=7\ units

substitute

Vc=7B\ units^{3}

step 3

Compare the volumes

we know that

The area of the base both figures are congruent

Find the ratio of their volumes

\frac{Vp}{Vc}

substitute

\frac{Vp}{Vc}=\frac{(\frac{10}{3}B)}{7B}

Simplify

\frac{Vp}{Vc}=\frac{10}{21}

21Vp=10Vc\\\\Vc=2.1Vp

therefore

The volume of the cylinder is 2.1 times the volume of the pyramid

MrRa [10]3 years ago
6 0

Answer:

Volume of right cylinder =2.1 times the volume of right pyramid

Step-by-step explanation:

We are given that Cross-sectional area of right pyramid and a right cylinder are congruent.

The height of pyramid =10 units

The height of right  cylinder =7 units

We have to find the conclusion that can be made from given information.

We know that Volume of right cylinder =\pi r^2h

Volume of right pyramid =\frac{1}{3}Bh

Where B=Area of base of pyramid

Volume of right  cylinder =\pi r^2{7}=7\pi r^2

We know that base area of right cylinder=B =\pi r^2

Therefore, volume of cylinder =7B

Volume of right pyramid =\frac{1}{3}\times 10\times B

Volume of right pyramid =\frac{10}{3} B

We are given that cross section area  of right pyramid is congruent to  cross section area of right cylinder

\frac{volume\;of\;\;right\;cylinder}{volume\;of\;right\;pyramid}=\frac{7B}{\frac{10}{3}B}

\frac{volume\;of\;right\;cylinder}{volume\;of\;right\;pyramid}=\frac{21}{10}=2.1

Volume of right cylinder =2.1 times the volume of right pyramid

Therefore, the conclusion is volume of cylinder is 2.1 times the volume of pyramid .

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