Pls help me. And thank you so so much!

2. Alleles that are both expressed in a heterozygote are

antiseptic1488 [7]

Answer:

incompletely dominent

Explanation:

because hetrozygouse like Hh is incompletely dominent. but it's dominent means it expresses the dominent allele H

7 0

3 years ago

Child 2 is polydactylous, otherwise normal; Child 4 has cystic fibrosis and is polydactylous.What is the genotype of the mother?

satela [25.4K]

Answer:

PpCc; ccpp; ccPp; 1/2

Explanation: The complete correct question is as follows

A polydactylous woman, otherwise normal, marries a healthy normal man. Their four children have the following phenotypes:

Child 1 is normal in all respects; Child 3 has cystic fibrosis, otherwise normal Child 2 is polydactylous, otherwise normal; Child 4 has cystic fibrosis and is polydactylous. A. What is the genotype of the mother? B. What is the genotype of child 3? C. What is the genotype of child 4? D. What is the chance that child 1 is heterozygous for cystic fibrosis?

We represent the traits of the parents with the following

P= Polydactyly

p=normal

C= normal

c= abnormal (cystic fibrosis

A. What is the genotype of the mother

Mother PpCc (polydactylous)

Father: ppCc (healthy normal)

B. What is the genotype of child 3?

Applying the mendel's cross link between the mother's genotype and father's genotype,

PpCc × ppCc

Child 3 will be ccpp (abnormal with cystic fibrosis)

C. What is the genotype of child 4?

Applying the mendel's cross link between the mother's genotype and father's genotype,

PpCc × ppCc

Child 4 will be ccPp

D. What is the chance that child 1 is heterozygous for cystic fibrosis?

Applying the mendel's cross link between the mother's genotype and father's genotype,

PpCc × ppCc

Child will be Cccc

The chance is 1/2

8 0

3 years ago

You have spent time working with a population of beetles. Sexually mature males range in size from 2-6 cm in length. You realize

babymother [125]

Answer:

Option B, No

Explanation:

Complete question is as follows -

You have spent time working with a population of beetles. Sexually mature males range in size from 2-6 cm in length. You realize that the females only mate with males that measure less than 3 cm long. If you measured allele frequencies at a single gene (locus) that contributes to overall length, would you expect this population to be in H-W equilibrium from one generation to the next?

Select one:

a. Yes

b. No

Solution -

No, because Hardy Weinberg’s equilibrium theory is not applicable in practical scenario as it assumes that H-W equilibrium persists from one generation to the other only when these is no disturbing factor . These disturbing factors include – natural selection, non-random mating, genetic drift, gene flow and mutations. Since this theory works only in an idealized state where no such disturbances occur, it is very difficult to say that the beetle population can remain in H-W equilibrium. Also the females in the beetle population are selecting the males for mating thereby exhibiting sexual selection. Hence, H-W equilibrium will not be applicable.

Hence, option B

5 0

3 years ago

Name the four types of particles found in the atmosphere.

Viefleur [7K]

Answer: Carbon Dioxide, Nitrogen, Argon, and oxygen.

Explanation: Earth's atmosphere is 78% nitrogen, 21% oxygen, 0.9% argon, and 0.03% carbon dioxide with very small percentages of other elements.

5 0

3 years ago

Read 2 more answers

As a population grows, which factor does not slow or limit the growth of the population include

xz_007 [3.2K]