Note that 1.485 is the same as 1485/1000, the ratio of two integers. Thus, 1.485 is rational.
(3y^7)^3 3^3*y^(7*3)
------------ = ------------------
9y^9 9*y^9
(3y^7)^3 3^3*y^(7*3) 27*y^21 (mult. together the exponents 3 and 7)
------------ = ------------------ = --------------
9y^9 9*y^9 9*y^9
That 27/9 reduces to 3. y^(21) / y^9 reduces to y^12.
Thus, we obtain 3*y^12 (answer)
Please do the next one, asking questions if need be, and showing your work.
Answer: a) k >4.08
b) k = 4.08
c) k<4.08
Step-by-step explanation:
Since we have given that
a) For what values of k will the function have no zeros?
It mean it has no real zeroes i.e. Discriminant < 0
As we know that
Here, a =-3
b = 7
c = -k
So, it becomes,
b) For what values of k will the function have one zero?
It means it has one real root i.e equal roots.
So, in this case, D = 0
So, it becomes,
c) For what values of k will the function have two zeros?
It means it has two real roots.
In this case, D>0
So, it becomes,
Hence, a) k >4.08
b) k = 4.08
c) k<4.08
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