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4 years ago

For the following inequality, indicate whether the boundary line should be dashed or solid.

2 answers:

7 0

So the problem ask to determine if the said inequality indicates where its boundary line should be dashed or solid but first you must consider that the solid should be used if the line is part of the solution and the dashed designates that the line is not part of the solution. Base on that, the answer would be SOLID. I hope you are satisfied with my answer

Fudgin [204]4 years ago

7 0

Hey! a dotted line is used for < and > while a solid one is used for ≤ and ≥
So in this case its... Solid :D

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there are 5 boxes of markers in the drawer. each box contains 24 markers and more than 60% of the markers are blue markers. Find

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Each box has twelve blue markers.. no i'm not 100% sure about this answer

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3 years ago

Simply 3/4 - (6 - 3/4s)

Viktor [21]

Answer:

-21/4 + 3s/4

Step-by-step explanation:

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3 years ago

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3 years ago

Jose earns $3680 per month, of which 22% is taken out of his paycheck for federal and state income taxes and other required dedu

ad-work [718]

Answer:

Step-by-step explanation:

Step one:

monthly earnings= $3680

22% of the earnings is

=22/100*3680

=0.22*3680

=$809.6

Jose's take home will be

3680-809.6

=$2870.4

Step two:

Required

percentage spent on rent and clothing

but the total cost of rent and clothing is

=775+86.12

=$861.12

percentage of rent and cloth is

=(861.12/2870.4)*100

=0.3*100

=30%

 The percentage is 30% of the take home

8 0

3 years ago

Autos arrive at a toll plaza located at the entrance to a bridge at a rate of 50 per minute during the 5:00-to-6:00 P.M. hour.

inna [77]

Answer:

a. The probability that the next auto will arrive within 6 seconds (0.1 minute) is 99.33%.

b. The probability that the next auto will arrive within 3 seconds (0.05 minute) is 91.79%.

c. What are the answers to (a) and (b) if the rate of arrival of autos is 60 per minute?

For c(a.), the probability that the next auto will arrive within 6 seconds (0.1 minute) is now 99.75%.

For c(b.), the probability that the next auto will arrive within 3 seconds (0.05 minute) is now 99.75%.

d. What are the answers to (a) and (b) if the rate of arrival of autos is 30 per minute?

For d(a.), the probability that the next auto will arrive within 6 seconds (0.1 minute) is now 95.02%.

For d(b.), the probability that the next auto will arrive within 3 seconds (0.05 minute) is now 77.67%.

Step-by-step explanation:

a. What is the probability that the next auto will arrive within 6 seconds (0.1 minute)?

Assume that x represents the exponential distribution with parameter v = 50,

Given this, we can therefore estimate the probability that the next auto will arrive within 6 seconds (0.1 minute) as follows:

P(x < x) = 1 – e^-(vx)

Where;

v = parameter = rate of autos that arrive per minute = 50

x = Number of minutes of arrival = 0.1 minutes

Therefore, we specifically define the probability and solve as follows:

P(x ≤ 0.1) = 1 – e^-(50 * 0.10)

P(x ≤ 0.1) = 1 – e^-5

P(x ≤ 0.1) = 1 – 0.00673794699908547

P(x ≤ 0.1) = 0.9933, or 99.33%

Therefore, the probability that the next auto will arrive within 6 seconds (0.1 minute) is 99.33%.

b. What is the probability that the next auto will arrive within 3 seconds (0.05 minute)?

Following the same process in part a, x is now equal to 0.05 and the specific probability to solve is as follows:

P(x ≤ 0.05) = 1 – e^-(50 * 0.05)

P(x ≤ 0.05) = 1 – e^-2.50

P(x ≤ 0.05) = 1 – 0.0820849986238988

P(x ≤ 0.05) = 0.9179, or 91.79%

Therefore, the probability that the next auto will arrive within 3 seconds (0.05 minute) is 91.79%.

c. What are the answers to (a) and (b) if the rate of arrival of autos is 60 per minute?

For c(a.) Now we have:

v = parameter = rate of autos that arrive per minute = 60

x = Number of minutes of arrival = 0.1 minutes

Therefore, we specifically define the probability and solve as follows:

P(x ≤ 0.1) = 1 – e^-(60 * 0.10)

P(x ≤ 0.1) = 1 – e^-6

P(x ≤ 0.1) = 1 – 0.00247875217666636

P(x ≤ 0.1) = 0.9975, or 99.75%

Therefore, the probability that the next auto will arrive within 6 seconds (0.1 minute) is now 99.75%.

For c(b.) Now we have:

v = parameter = rate of autos that arrive per minute = 60

x = Number of minutes of arrival = 0.05 minutes

Therefore, we specifically define the probability and solve as follows:

P(x ≤ 0.05) = 1 – e^-(60 * 0.05)

P(x ≤ 0.05) = 1 – e^-3

P(x ≤ 0.05) = 1 – 0.0497870683678639

P(x ≤ 0.05) = 0.950212931632136, or 95.02%

Therefore, the probability that the next auto will arrive within 3 seconds (0.05 minute) is now 99.75%.

d. What are the answers to (a) and (b) if the rate of arrival of autos is 30 per minute?

For d(a.) Now we have:

v = parameter = rate of autos that arrive per minute = 30

x = Number of minutes of arrival = 0.1 minutes

Therefore, we specifically define the probability and solve as follows:

P(x ≤ 0.1) = 1 – e^-(30 * 0.10)

P(x ≤ 0.1) = 1 – e^-3

P(x ≤ 0.1) = 1 – 0.0497870683678639

P(x ≤ 0.1) = 0.950212931632136, or 95.02%

Therefore, the probability that the next auto will arrive within 6 seconds (0.1 minute) is now 95.02%.

For d(b.) Now we have:

v = parameter = rate of autos that arrive per minute = 30

x = Number of minutes of arrival = 0.05 minutes

Therefore, we specifically define the probability and solve as follows:

P(x ≤ 0.05) = 1 – e^-(30 * 0.05)

P(x ≤ 0.05) = 1 – e^-1.50

P(x ≤ 0.05) = 1 – 0.22313016014843

P(x ≤ 0.05) = 0.7767, or 77.67%

Therefore, the probability that the next auto will arrive within 3 seconds (0.05 minute) is now 77.67%.

8 0

3 years ago