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KiRa [710]
3 years ago
11

How do I find these equations using substitution y=-3x+5 and 5x-4y=-3 ?

Mathematics
2 answers:
NISA [10]3 years ago
7 0

Answer:

(1,2)

Step-by-step explanation:

1) To solve using substitution, first isolate one of the variables in one of the equations. However, the y in y = -3x + 5 has already been isolated, so we don't need this step. Instead, take that value of y and substitute it for the y in the other equation, 5x - 4y = -3. So, substitute -3x + 5 for the y in 5x - 4y = -3 and solve:

5x-4(-3x+5)= -3\\5x+12x-20=-3\\17x-20=-3\\17x = 17\\x = 1

2) So, x = 1. Now, take that value of x and substitute back into any of the equations to find the y value. (I chose to substitute it into y = -3x + 5, but either choice is fine). So, substitute 1 for the x in y = -3x + 5 and solve:

y = -3(1)+5\\y = -3+5\\y = 2

So, y = 2. Thus, by knowing both x and y values, the solution would be (1,2).

lapo4ka [179]3 years ago
6 0

Answer:

x=1

Step-by-step explanation:

you would change it to 5x-4(-3x+5)=-3, because you put the info for the first equation into the second equation.

5x-4(-3x+5)=-3

5x+12x-20=-3

17x-20=-3

17x=17

x=1

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A television Mark 1600 was sold for 1200 what percent discount was given on that television​
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Answer:

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Step-by-step explanation:

Discount = 1600 - 1200 = 400

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A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40
bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. How large was the sample used in this survey?

We have that s = 25, \sigma = 400. We want to find n, so:

s = \frac{\sigma}{\sqrt{n}}

25 = \frac{400}{\sqrt{n}}

25\sqrt{n} = 400

\sqrt{n} = \frac{400}{25}

\sqrt{n} = 16

(\sqrt{n})^2 = 16^2[tex][tex]n = 256

A sample of 256 was used in this survey.

b. What is the probability that the point estimate was within ±15 of the population mean?

15 is the bounds with want, 25 is the standard error. So

Z = 15/25 = 0.6 has a pvalue of 0.7257

Z = -15/25 = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

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