Can someone help me with this please???...

Three pairs of gloves- a red pair, a blue pair, and a green pair-are in a drawer. If the gloves are removed at random without re

balandron [24]

Answer:

4

Step-by-step explanation:

Given that three pairs of gloves- a red pair, a blue pair, and a green pair-are in a drawer. The gloves are removed at random without returning any to the drawer.

We have to find the minimum number that must be removed in order to guarantee having a matched pair of gloves

No of different colours = 3 (red, blue, green)

Hence no of gloves that must be removed = 3+1

If 4 gloves are removed, only 3 can be of different colours 1 will have same colour as any one of the three.

So a pair of same colour would be obtained

Answer is 4

8 0

3 years ago

Triangle ABC has the following properties: Angle A measures 120°; AB ≅ AC. What is the classification of triangle ABC by angles

Flura [38]

The answer is C <<<=====
It can't be anything else. It is not a right angle. A>90
It can't be acute because one angle is greater than 90.
It can't scalene because at least 2 of the angles (and 2 sides) are equal.

8 0

3 years ago

The table shows the length of four tracks on an album and the total number of beats in that song.

swat32

Track 1, Track 3, Track 2, Track 4

3 0

3 years ago

Round 205,000 to the nearest ten thousand

Eddi Din [679]

200,000 is ur answer u welcme

7 0

3 years ago

Read 2 more answers

According to these three facts, which statements are true?

Yanka [14]

Q1) We have the following statements:

1. Circle W has center (−3, 0) and radius 8.

We can write this statement as the following equation:

 $(x-h)^2+(y-k)^2=r^2 \therefore (h,k)=(-3,0) \ and \ r=8 \\ \\ \therefore (x+3)^2+y^2=64$

The graph of this equation is shown in Figure 1.

2. Circle V is a translation of circle W, 2 units down.

To do this translation we add two units to the y-coordinate, so:

 $(x+3)^2+(y+2)^2=64$

The graph is shown in Figure 2.

3. Circle V is a dilation of circle W with a scale factor of 2.

To do this dilatation we multiply both the center and the radius by the scale factor of 2, thus:

 $(x+3)^2+y^2=64 \\ (h,k)=(-3,0) \\ (h_v,k_v)=2\times (-3,0)=(-6,0) \ and \ r_v=8\times2=16 \\ \\ (x+6)^2+y^2=256$

This circle is shown in Figure 3

So let's analyze each statement.

Q1.1) The center of circle V is (−5, 0).

This is false. From the statement 2 we know that the new center is (-3, -2) and from 3 the new center is (-6, 0).

Q1.2) Circle V and circle W are similar.

Since all circles have the same shape even though they may be different sizes, then all circles are similar. Therefore, it is true that circle V and circle W are similar.

Q1.3) The radius of circle V is 16.

From the statement 3 we can affirm that this is true. By applying the dilatation with a scale factor of 2 we find out that the radius of the new circle is in fact equal to 16.

Q1.4) Circle V and circle W have the same center.

From the statement 2 we know that the new center is (-3, -2) and from 3 the new center is (-6, 0). On the other hand, the center of circle W is (-3, 0). From this, it follows that this statement is false.

Q2) Suppose x is any positive number.

We have two concentric circles as follows:

$x\ \textgreater \ 0 \\ \\ Circle \ 1: Center \ (0,0) \ and \ radius \ 2x \\ \\ Circle \ 2: Center \ (0, 0) \ and \ radius \ 10x$ 

Q2.1) Why is circle 1 similar to circle 2?

If we perform a dilatation, that is, a resizing of one circle, centered on the shared center, until both circles overlap, it will be true that the circles will always overlap no matter what size they are, thus, they are similar. In fact, as we said in above all circles are similar.

Q2.2) Circle 2 is a dilation of circle 1 with a scale factor of 0.2.

Suppose that:

 $x=2$

Then circle 1 is given by the following equation:

 $x^2+y^2=4$

If we dilate this circle with a scale factor of 0.2 then:

 $Circle \ 1: x^2+y^2=4 \\ Diameter \ 1=2r=2\times 2=4 \\ \\ (h,k)=(0,0) \\ (h_v,k_v)=0.2\times (0,0)=(0,0) \ and \ r_v=0.2\times 2=0.4 \\ \\ Circle \ 2:x^2+y^2=0.16 \\ Diameter \ 2=2\times 0.4=0.8 \\ \\ So: \\ \\ Diameter \ 1 \neq Diameter \2$

So the statement both circles have congruent diameters is false.

Q2.3) Circle 2 is a dilation of circle 1 with a scale factor of 5.

We have the same equation for circle 1:

 $x^2+y^2=4$

$Circle \ 1: x^2+y^2=4 \\ \\ Dilatation: \\ (h,k)=(0,0) \\ (h_v,k_v)=5\times (0,0)=(0,0) \ and \ r_v=5\times 2=10 \\ \\ Circle \ 2:x^2+y^2=100$

Two circles have the same area if they have the same radius. Given that this is no applied to our circles, the statement circle 1 and circle 2 have equal areas is false.

8 0

3 years ago