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2 years ago

12

Ayuda please I need help me please

1 answer:

snow_tiger [21]2 years ago

4 0

Answer:

sqrt(61)

Step-by-step explanation:

4-(-1) = 5

-3-(-9) = 6

sqrt(5^2+6^2) = sqrt(25+36) = sqrt(61)

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PLS HELP! DUE TODAY

Ostrovityanka [42]

Answer:

3 I think not sure.........

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3 years ago

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What is the quotient (6x4 − 15x3 + 10x2 − 10x + 4) ÷ (3x2 + 2)?

Marrrta [24]

Answer:

The quotient is $2x^2-5x+2$

Step-by-step explanation:

We want to simplify:

$\frac{6x^4-15x^3+10x^2-10x+4}{3x^2+2}$

We factor the numerator to get:

$\frac{(x-2)(2x-1)(3x^2+2)}{3x^2+2}$

We cancel out the common factors to get:

$(x-2)(2x-1)$

Therefore the quotient is $2x^2-5x+2$

8 0

3 years ago

How to write 3,516.568 in expanded form

gogolik [260]

3,000.000 + 500.000 + 16.000 + 500 + 60 + 8 - Hope it helps!

6 0

3 years ago

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Multiply or divide. Show your work.<br><br> 3n²-n/n²-1÷n²/n+1

Ugo [173]

$\frac{3n^{2} - n}{n^{2} - 1} \div \frac{n^{2}}{n + 1}$
$\frac{n(3n) - n(1)}{n^{2} + n - n - 1} \div \frac{n^{2}}{n + 1}$
$\frac{n(3n - 1)}{n(n) + n(1) - 1(n) - 1(1)} \div \frac{n^{2}}{n + 1}$
$\frac{n(3n - 1)}{n(n + 1) - 1(n + 1)} \div \frac{n^{2}}{n + 1}$
$\frac{n(3n - 1)}{(n - 1)(n + 1)} \div \frac{n^{2}}{n + 1}$
$\frac{n(3n - 1)}{(n - 1)(n + 1)} * \frac{n + 1}{n^{2}}$
$\frac{3n - 1}{n - 1} * \frac{1}{n}$
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5 0

3 years ago

The number of members over time in an online music sharing club can be modeled by an exponential function. the club started with

Paraphin [41]

Answer:

a.) $N(x) = N_{0} e^{bx}$

b.) therefore b = $\ln \frac{2142}{2100} = \ln (1.02) = 0.0198$

b is the rate of increase of number of members

c.) The club will not be able to get more than 5000 members during its first year.

Step-by-step explanation:

i) the club started with 2100 members.

so we can write $N_{0}$ = 2100.

a.) so we can write the equation as an exponential function given by

$N(x) = N_{0} e^{bx}$ where x is in months and b is a constant and N(x) is the number of members in the online music sharing club .

therefore 2142 = 2100 $\times (e^{b\times 1})$ = 2100 $e^{b}$

b.) therefore b = $\ln \frac{2142}{2100} = \ln (1.02) = 0.0198$

b is the rate of increase of number of members

c.) Will the club have more than 5000 members during its first year? Justify your reasoning.

5000 = 2100 $e^{0.0198x}$

therefore x = $\frac{1}{0.0198} \ln{(\frac{5000}{2100} )} = 43.81 \hspace{0.1cm}months$

The club will not be able to get more than 5000 members during its first year.

7 0

3 years ago