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3 years ago

Can someone help me plss! ?

Mathematics

1 answer:

Ann [662]3 years ago

5 0

Sry but that’s too much which one would you like help on

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A plane traveled 240 miles. The trip was with the wind. It took 3 hours. The trip back was into the wind. The trip back took 6 h

sveta [45]

Answer:

Plane speed is 60 miles/hour

Wind speed is 20 miles/hour

Step-by-step explanation:

Lets suppose the speed of the plane in still air is s and speed of the wind is w and since speed in the formula below equals speed of the plane plus the wind's speed so speed=s+w for this journey with the wind

$Speed=\frac{Distance}{Time}$

$Distance=Speed*Time$

For the first journey the trip with the wind:

$Distance=Speed*Time\\240=(s+w)(3)\\240/3=s+w\\s+w=80$

Here we got our first equation for the second equation we use the information from the second trip which was into the wind. Which means the speed here would be speed=s-w

$Distance=Speed*Time\\240=(s-w)*6\\240/6=s-w\\s-w=40$

so now we got our two equations adding both equations would result into the following:

$s+w=80\\s-w=40\\2s=120\\s=60$

so speed of the plane is 60 miles/hour put the value of s in any our two equations to calculate the wind speed, lets take the first equation:

$s+w=80\\60+w=80\\w=80-60\\w=20$

so the wind speed is 20 miles/hour

8 0

3 years ago

Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

3 years ago

7/10 × 4/21. Show your work

wolverine [178]

Answer:

Step-by-step explanation:

7/10 × 4/21

1/5 *2/3 =2/15

reduce them down

6 0

3 years ago

Hii, Ok so basically I really need help with these questions they are really difficult and don't worry rewards are plenty a come

posledela

So begin by doing 360-284=76
90+76=166
180-166=14

X=14

5 0

3 years ago

The ruby-throated hummingbird has a wing beat of about 200 beats per second. About how many wing beats would a hummingbird have

aleksley [76]

So,
To get how many wingbeats per minute,
200x60=12000 because there are 60 seconds in a minute
To get how many in 3 minutes,
12000x3=36000

Hope I helped!

6 0

4 years ago

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