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lana [24]
2 years ago
15

Students in a school are asked to pick either football, rugby or tennis to play in their lesson.

Mathematics
1 answer:
grin007 [14]2 years ago
5 0

Step-by-step explanation:

let x be rubgy liked let y football liked

x/125=12/25

ansx=60

again

y/60=5/4

ans y=75

football liked students are 75

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Triangle angle sum theorem<br> What is the value of z?
prisoha [69]

Answer:

z=3

Step-by-step explanation:

→32+76+24z=180[Sum of all sides of a triangle]

→108+24z=180

→24z=180-108

→z=72/24

→z=3

7 0
2 years ago
Read 2 more answers
The rate at which rain accumulates in a bucket is modeled by the function r given by r(t)=10t−t^2, where r(t) is measured in mil
mars1129 [50]

Answer:

36 milliliters of rain.

Step-by-step explanation:

The rate at which rain accumluated in a bucket is given by the function:

r(t)=10t-t^2

Where r(t) is measured in milliliters per minute.

We want to find the total accumulation of rain from <em>t</em> = 0 to <em>t</em> = 3.

We can use the Net Change Theorem. So, we will integrate function <em>r</em> from <em>t</em> = 0 to <em>t</em> = 3:

\displaystyle \int_0^3r(t)\, dt

Substitute:

=\displaystyle \int_0^3 10t-t^2\, dt

Integrate:

\displaystyle =5t^2-\frac{1}{3}t^3\Big|_0^3

Evaluate:

\displaystyle =(5(3)^2-\frac{1}{3}(3)^3)-(5(0)^2-\frac{1}{3}(0)^3)=36\text{ milliliters}

36 milliliters of rain accumulated in the bucket from time <em>t</em> = 0 to <em>t</em> = 3.

4 0
3 years ago
Help me solve thanks
Inessa [10]
Answer is (A) x < 14/5
(B) x < -21/4
7 0
2 years ago
Find the lateral and surface area of the figure.
katovenus [111]
The lateral and surface area of the figure is 21
8 0
3 years ago
What is the value of a when we rewrite 8^x as a^-x/9​
Andre45 [30]

Answer:

a = \frac{1}{134217728}

Step-by-step explanation:

Given

8^x = a^{-x/9}

Required

Find a

Take log of both sides

log(8^x) = log(a^{-x/9})

Apply law of logarithm

x\ log(8)  = (-x/9) log(a)

Divide both sides by a

log(8)  = -\frac{1}{9} log(a)

Multiply both sides by -9

-9\ log(8)  = log(a)

Apply law of logarithm

log(8^{-9})  = log(a)

Cancel out log

8^{-9}  = a

Rewrite as:

a = 8^{-9}

Apply law of indices

a = \frac{1}{8^9}

a = \frac{1}{134217728}

4 0
3 years ago
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