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Usimov [2.4K]
2 years ago
11

In a shop, a TV has a normal price of £500

Mathematics
1 answer:
andrey2020 [161]2 years ago
3 0

Answer:

400> 360

Step-by-step explanation:

1/10 X 500 = 50

500 - 50 = 450

10% = 450/ 10 = 45

20% = 45 x 2 = 90

450 - 90 = 360

Chris does have enough 400> 360

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(**15 POINTS**)
bonufazy [111]

Answer:

0.6x = 87

Step-by-step explanation:

Hi, to answer this question we have to write en equation:

We have to multiply the variable x by the percentage given (60%) in decimal form (divided by 100). That expression must be equal to 87.

Mathematically speaking:

x (60/100) = 87

0.6x = 87

Feel free to ask for more if needed or if you did not understand something.

8 0
3 years ago
PLEASE HELP EASY WORK GIVING BRAINLIEST REPORTING FALSE ANSWERS
LuckyWell [14K]
It is 70 because common sense people
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3 years ago
What is the greatest possible product of a 2 digit number and a 1 digit number?
sladkih [1.3K]
Highest 2-digit number = 99 
<span>Highest 1-digit number = 9 </span>
<span>Highest possible sum from 2, 2-digit numbers = 198 </span>
<span>Highest possible sum from 2, 1-digit numbers = 18</span>
5 0
3 years ago
Read 2 more answers
During one game, the Heat made 12 free throws. If their free throw percentage is 75%, how many free throws were attempted?
HACTEHA [7]

Answer:

16

Step-by-step explanation:

12 = 75%

4 = 25%

4 x 4 = 16

16 = 100%

Sorry if it's confusing but that's just how I think of it.

5 0
3 years ago
Read 2 more answers
a food snack manufacturer samples 9 bags of pretzels off the assembly line and weights their contents. If the sample mean is 14.
gladu [14]

Answer:

<h2>13.7≤\mu≤14.7</h2>

Step-by-step explanation:

The formula for calculating the confidence interval is expressed as shown;

CI = xbar ± Z(б/√n)

xbar is the sample mean

Z is the value at 95% confidence interval

б is the standard deviation of the sample

n is the number of samples

Given xbar = 14.2, Z at 95% CI = 1.96, б = 0.70 and n = 9

Substituting this values into the formula;

CI = 14.2 ± 1.96(0.70/√9)

CI = 14.2 ± 1.96(0.70/3)

CI = 14.2 ± 1.96(0.2333)

CI = 14.2 ± 0.4573

CI = (14.2-0.4573, 14.2+0.4573)

CI = (13.7427, 14.6537)

Hence, the 95% confidence interval of the true mean is within the range

13.7≤\mu≤14.7 (to 1 decimal place).

6 0
3 years ago
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