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mars1129 [50]
3 years ago
15

What is the equation of the line that passes through the point (-7,-4) and has a slope of 11?

Mathematics
1 answer:
NikAS [45]3 years ago
5 0

Answer:

y=11x+73

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)
  • y and x stay the same but m and b are replaced with numerical values

<u>1) Plug the slope into </u>y=mx+b<u> (m)</u>

y=11x+b

<u>2) Plug the given point into the equation and solve for b</u>

y=11x+b\\-4=11(-7)+b\\-4=-77+b

Add 77 to both sides to isolate b

-4+77=-77+b+77\\73=b

Plug b back into y=11x+b

y=11x+73

I hope this helps!

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One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times sm
sergey [27]

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel

<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.  

We have to prove that the lines are parallel.

If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

Now, the 1st angle will be 1/6 of right angle is given as:

\begin{array}{l}{\rightarrow 1^{\text {st }} \text { angle }=\frac{1}{6} \times 90} \\\\ {\rightarrow 1^{\text {st }} \text { angle }=15 \text { degrees }}\end{array}

And now, 15 degrees is 11 times smaller than the other  

Then other angle = 11 times of 15 degrees

\text {Other angle }=11 \times 15=165 \text { degrees }

Now, sum of angles = 15 + 165 = 180 degrees.

As we expected their sum is 180 degrees. So the lines are parallel.

Hence, the given lines are parallel

5 0
4 years ago
Given g(x)= -2x+2 and f(x)= 3x^2+4, find (g+f)(-3)
aliina [53]

Answer:

39

Step-by-step explanation:

g(x)= -2x+2 and f(x)= 3x^2+4

(g+f)(-3)

g(-3) = -2(-3) +2 = 6+2 =8

f(-3) = 3 (-3)^2 +4 = 3(9)+4 = 27+4 = 31

(g+f)(-3) = g(-3) + f(-3) = 8+31 = 39

3 0
4 years ago
You have a ruler of length 1 and you choose a place to break it using a uniform probability distribution. Let random variable X
salantis [7]

Answer:

Step-by-step explanation:

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6 0
3 years ago
If 2x+y=8 and x-1=y then what is y? Please be detailed I want to know more then just the answer but how to solve
IgorLugansk [536]
This is Bridge Algebra 2 stuff. Well you see that 2x+y=8 and x-1=y. To slove for y you have to slove for x first to find y. So 2x+x-1=8 ( the reason I did that is because there is a y in that equation and I placed it on that equation) now lets slove this equation for x. So 3x-1=8( I add 2x with x) 3x=9 ( I made -1 a positive one and add it to 8) x=3 ( I divided 9/3 to get 3). Now that you have slove x we will use x to slove for y. So 3-1=y, 2=y. Your answer is y=2.
4 0
3 years ago
If g (x) = 1/x then [g (x+h) - g (x)] /h
lys-0071 [83]

Answer:

\dfrac{-1}{x(x+h)}, h\ne 0

Step-by-step explanation:

If g(x) = \dfrac{1}{x}, then g(x+h) = \dfrac{1}{x+h}. It follows that

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

  = \dfrac{-1}{x(x+h)}, h\ne 0

5 0
3 years ago
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