Answer:air, water, and organisms in water
Explanation:
read the passage
Answer:
Mg(s) +<em> 2</em> HCl (aq) → H₂(g) + MgCl₂
0.415g of H₂(g) <em>-Assuming mass of Mg(s) = 10.0g-</em>
Explanation:
Balancing the reaction:
Mg(s) + HCl (aq) → H₂(g) + MgCl₂
There are in products two atoms of H and Cl, the balancing equation is:
Mg(s) +<em> 2</em> HCl (aq) → H₂(g) + MgCl₂
<em>Assuming you add 10g of Mg(s) -Limiting reactant-</em>
<em />
10g of Mg are (Atomic mass: 24.305g/mol):
10g × (1 mol / 24.305g) = <em>0.411 moles of Mg</em>
<em>-Theoretical yield is the amount of product you would have after a chemical reaction occurs completely-</em>
Assuming theoretical yield, as 1 mole of Mg(s) produce 1 mole of H₂(g), theoretical yield of H₂(g) is 0.411moles H₂(g). In grams:
0.411mol H₂(g) × (1.01g / mol) = <em>0.415g of H₂(g)</em>
Answer: 
concentration of 
= 0.50 M
concentration of 
= 0.25 M
Explanation:
The dissociation equation of 
is:
According to stoichiometry:
1 mole of gives 2 moles of
Thus 0.25 moles of gives =
moles of
Similarly,
1 mole of gives = 1 mole of
Thus 0.25 moles of gives =
moles of
Thus the concentration of and are 0.50 M and 0.25 M respectively.
Answer: option b) 1 dg
Explanation:
1) These are the different equivalences of those quantities:
a) 1 g = 100 cg ⇒ 1 cg = 0.01 g
b) 1 g = 10 dg ⇒ 1 dg = 0.1 g
c) 1 g = 1000 mg ⇒ 1 mg = 0.001 g
d) 1g = 10⁹ g ⇒ 1 ng = 10 ⁻⁹g
2) Now that you have all the masures in grams you can compare:
0.1g > 0.01g > 0.001g > 10 ⁻⁹g
3) So, the largest value is 0.1g which is 1 dg.
In determining the boiling point
of solutions, always take note of the number of ions that will dissociate in
the solution. It does not depend on the nature of the substance. The greater
the number of ions dissociated, the greater is the boiling point of the solution.
