An unknown sample of mystery element T is analyzed. According to the data 7.42% of the element is ^6T and 92.58% is ^7T. The tru
1 answer:
Answer:
Explanation:
1. Atomic mass of T
To get the atomic mass of T, you calculate the weighted average of the atomic masses of the isotopes.
That is, you multiply the atomic mass of each isotope by a number representing its relative importance (e.g.., its percent of the total).
2. Identity of T
Lithium has an atomic mass of 6.64 u.
Element T is lithium.
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where, E^{o} (Ag+/Ag) = std. reduction potential of Ag+ = 0.7994 v
and Sn2+/Sn = std. reduction potential of Sn2+ = -0.14 v
Thus, E^{o}cell = 0.7994v - (-0.14v) = 0.9394 v
Now, ΔG^{o} = -nF
where, n = number of electrons = 2
F = Faraday's constant = 96500 C
∴ΔG^{o} = 2 X 96500 X 0.9394 = -1.18 X
Now, using Nernst's Equation we have,
E_{cell} = 0.9765 v
Finally, ΔG = -nFE = -2 X 96500 X 0.9765 = -1.88 X
Answer:
The cell potential is 0.0296V
Explanation:
Please see the attachment below
