All categories

3 years ago

Which of the following mass units is the largest? a) 1 cg b) 1 dg c) 1 mg d) 1 ng

Chemistry

2 answers:

N76 [4]3 years ago

4 0

Answer: option b) 1 dg

Explanation:

1) These are the different equivalences of those quantities:

a) 1 g = 100 cg ⇒ 1 cg = 0.01 g

b) 1 g = 10 dg ⇒ 1 dg = 0.1 g

c) 1 g = 1000 mg ⇒ 1 mg = 0.001 g

d) 1g = 10⁹ g ⇒ 1 ng = 10 ⁻⁹g

2) Now that you have all the masures in grams you can compare:

0.1g > 0.01g > 0.001g > 10 ⁻⁹g

3) So, the largest value is 0.1g which is 1 dg.

Fittoniya [83]3 years ago

4 0

Which of the following mass units is the largest?

b) 1 dg

You might be interested in

How many moles of AlCl3 are formed by 1.53 moles of CuCl2?

jolli1 [7]

Answer:

1.02 moles of AlCl3

Explanation:

Consider the balanced reaction equation shown below;

2Al(s) + 3CuCl2(aq) -------> 2AlCl3 (aq) + 3Cu(s)

This is the balanced reaction equation for the reaction going on above. Recall that the first step in solving any problem is to accurately put down the chemical reaction equation. This balanced reaction equation always serves a reliable guide in solving the problem at hand.

Given that;

3 moles of CuCl2 yields 2 moles of AlCl3

1.53 moles of CuCl2 yields 1.53 × 2 / 3 =1.02 moles of AlCl3

5 0

3 years ago

Predict the shape and hybridization of platinum tetrachloride (PfCl4)

guapka [62]

Answer:

Shape- square planar , hybridisation-sp3

Explanation:

Shape:

VSPER theorey is used to determine both electron geometry and molecular geometry of a molecule.(PtCl4)2 molecular geometry is square planar
Hybridisation:It undergoes sp3 hybridisation.since there are 2 unpaired electrons in this case, it is paramagnetic in nature

3 0

3 years ago

Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t

Vitek1552 [10]

Answer: The mass of decane produced is $1.743\times 10^2g$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

$\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol$

The chemical equation for the hydrogenation of decene follows:

$C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)$

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = $\frac{1}{1}\times 1.225=1.225mol$ of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

$1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g$

Hence, the mass of decane produced is $1.743\times 10^2g$

5 0

3 years ago

2. 27.8 mL of an unknown were added to a 50.0-mL flask that weighs 464.7 g. The total mass of the flask and the liquid is 552.4

agasfer [191]

Answer:

$d=4.24x10^{-4}\frac{lb}{in^3}$

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

$d=\frac{m}{V}$