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mariarad [96]
3 years ago
5

M∠RST =______because they are __________ (Fill in the blanks)

Mathematics
1 answer:
iogann1982 [59]3 years ago
6 0

Answer:

∠RST = ∠SRU because they are alternate angles.

Step-by-step explanation:

Hope it helps .

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Find the missing dimension of the cylinder. round your answer to the nearest whole number
Ulleksa [173]

Answer:

11 meters

Step-by-step explanation:

Use the formula:

V = \pi r^{2} h

V = 7599, h = 20, π = 3.14

Plugin the numbers and solve for r

7599=3.14(20)r^{2} \\7599=62.8r^{2} \\7599/62.5=62.8r^{2} /62.8\\121=r^{2} \\\sqrt{121}=\sqrt{r^{2} } \\r=11

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2 years ago
PLEASE PLEASE HELP ME
grin007 [14]
Ok so first what you gotta do is carry the 1 to the 7 which makes 8 minus 1 is 7 so your answer is D
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3 years ago
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72kg in a ratio of 1:3:5
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first of all you add all of the ratios together so it would be 1+3+5 That equals 9 then divide 72 by 9 which gets you 8. Then you times 8 by all of the ratios to get the answer 8:24:40
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3 years ago
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Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}

r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

(x-(-2))^2+(y-0)^2=\sqrt{5} ^2

on simplification is

x^{2} +y^{2}+4 x-1=0

5 0
3 years ago
WILL MARK AS BRAINIEST AND 35 POINTS
Sauron [17]

Answer: The answer is 11! I hope this helps! :)



Step-by-step explanation:


8 0
3 years ago
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