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2 years ago

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The area of a sector of a circle is given by the equation uppercase A = StartFraction pi r squared uppercase S Over 360 EndFract

ion, where r is the radius of the circle and S is the angle measure of the sector.

1 answer:

Ganezh [65]2 years ago

8 0

Answer:360A/pi ^2

Step-by-step explanation:

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Write and equation with aa variable on both sides of the equal sign that has infinitely many solutions. solve the equation and e

LekaFEV [45]

X = x

to solve, subtract both sides by x:

0 = 0

x is always equals to x so infinite solutions

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3 years ago

Can someone help me with the areas?

9966 [12]

Answer:

for 1. it is 99 and for 3. it is 343.75

Step-by-step explanation:

for 1. you have to just multiply the length with width

for 3. you have to add both bases (35+20) and multiply the height (55 x 12.5) to it and then divide it by 2 (687.5 / 2)

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2 years ago

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PLEASE HELP!!! PLATO ALGEBRA 2

andrey2020 [161]

Answer:

(gof) (4) = 9

Hence, option A is true.

Step-by-step explanation:

f(x)=-x³

g(x)=|1/8x -1|

(gof) (4) = g{f(4)}

First wee need to determine f(4)

f(4)=-(4)³

= -64

so

(gof) (4) = g{f(4)} = g(-64)

= $\left|\frac{1}{8}\left(-64\right)-1\right|$

$=\left|-\frac{1}{8}\cdot \:64-1\right|$

$=\left|-8-1\right|$

$=\left|-9\right|$

$\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a$

$=9$

Thus,

(gof) (4) = 9

Hence, option A is true.

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2 years ago

Show all work to factor x^4 − 17x^2 + 16 completely.

FrozenT [24]

Answer:

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2 years ago

a rectangular lawn has an area of a^3 - 125. use the difference of cubes to find out the dimensions of the rectangle.

ANEK [815]

The area of a rectangle is the product of its dimensions

The dimensions of the rectangle are: $\mathbf{Length = a -5}$ and $\mathbf{Width = a^2 + 5a + 25}$

The area is given as:

$\mathbf{Area = a^3 - 125}$

Express 125 as 5^3

$\mathbf{Area = a^3 - 5^3}$

Apply difference of cubes

$\mathbf{Area = (a - 5)(a^2 + 5a + 5^2)}$

$\mathbf{Area = (a - 5)(a^2 + 5a + 25)}$

The area of a rectangle is:

$\mathbf{Area = Length \times Width}$

So, by comparison:

$\mathbf{Length = a -5}$

$\mathbf{Width = a^2 + 5a + 25}$

Read more about areas at:

brainly.com/question/3518080

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2 years ago