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DochEvi [55]
3 years ago
9

Find the area of the sector.

Mathematics
1 answer:
nadezda [96]3 years ago
3 0
Ans. 11.16 in square
80/360*pi*4square
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RUDIKE [14]
Angle a is 22.62 degrees
and
angle b is 67.38 degrees

7 0
3 years ago
Please fill in the blanks! :D
ivann1987 [24]

Step-by-step explanation:

i think this is what you are asking for

5 0
3 years ago
What is the area of the pentagon, rounded to the nearest tenth?
Rudik [331]

The area of the pentagon, rounded to the nearest tenth will be 32.7 square cm. Then the correct option is C.

<h3>What is a polygon?</h3>

The polygon is a 2D geometry that has a finite number of sides. And all the sides of the polygon are straight lines connected to each other side by side.

A regular pentagon has an apothem measuring 3 cm and a perimeter of 21.8 cm.

Then the side length of the pentagon will be

5 x Side length = 21.8 cm

     Side length = 4.36 cm

Then the area of the pentagon, rounded to the nearest tenth will be

Area of pentagon = 5 x area of triangle

Area of pentagon = 5 x 1/2 x 4.36 x 3

Area of pentagon = 32.7 square cm

Thus, the correct option is C.

More about the polygon link is given below.

brainly.com/question/17756657

#SPJ1

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B2%7D-1%7D%7B2-5a%7D%20times%20%5Cfrac%7B15a-6%7D%7Ba%5E%7B2%7D%2B5a-6%7D" id=
stepan [7]
\bf \cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\\\\&#10;-----------------------------\\\\&#10;recall\quad \textit{difference of squares}&#10;\\ \quad \\&#10;(a-b)(a+b) = a^2-b^2\qquad \qquad &#10;a^2-b^2 = (a-b)(a+b)\\\\&#10;thus\quad a^2-1\iff a^2-1^2\implies (a-1)(a+1)&#10;\\\\\\&#10;now\quad a^2+5a-6\implies (a+6)(a-1)\\\\&#10;-----------------------------\\\\&#10;thus&#10;\\\\\\&#10;\cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\implies \cfrac{(a-1)(a+1)}{2-5a}\times \cfrac{3(5a-2)}{(a+6)(a-1)}\\\\&#10;-----------------------------\\\\&#10;

\bf now\quad 3(5a-2) \iff -3(2-5a)\\\\&#10;-----------------------------\\\\&#10;thus&#10;\\\\\\&#10;\cfrac{\underline{(a-1)}(a+1)}{\underline{2-5a}}\times \cfrac{-3\underline{(2-5a)}}{(a+6)\underline{(a-1)}}\implies \cfrac{-3(a+1)}{a+6}
6 0
3 years ago
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