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2 years ago

What is the probability of rolling a six on a fair die?

Mathematics

1 answer:

ExtremeBDS [4]2 years ago

5 0

Answer: 1/6

Step-by-step explanation: To find the probability of rolling a six,

let's use our ratio for the probability of an event.

<em>number of favorable outcomes / total number of outcomes</em>

Since only one side of a die has a six on on it, the number of favorable

outcomes for rolling a six is 1 and since there are six sides to a die and it's

equally likely that the die will landy on any of these sides, the total number

of outcomes is 6.

So the probability of rolling a six is 1/6.

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one eighth of the brass instruments are tubas. if there are 240 instruments in the band, how many are tubas?

Andrej [43]

Just do 240 times 1/8 which is the same thing as 240/8, which is 30

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3 years ago

There are 60 chocolates in a box

nika2105 [10]

There could be 35 toffees in the box.

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3 years ago

If x = false and y = false, is the statement: not x or not y<br> a) true<br> b) false

pantera1 [17]

Answer:

false

Step-by-step explanation:

X is equal to Y

therefore,

X = Y

X= false

Y = false

so,

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2 years ago

The sets of numbers 3, 4, 5 and 8, 15, 17 are Pythagorean triples. Use what you know about the Pythagorean Theorem and explain o

konstantin123 [22]

Answer:

When we have 3 numbers, like:

a, b and c.

Such that:

a < b < c.

These numbers are a Pythagorean triplet if the sum of the squares of the two smaller numbers, is equal to the square of the larger number:

a^2 + b^2 = c^2

This is equivalent to the Pythagorean Theorem, where the sum of the squares of the cathetus is equal to the hypotenuse squared.

Now that we know this, we can check if the given sets are Pythagorean triples.

1) 3, 4, 5

Here we must have that:

3^2 + 4^2 = 5^2

solving the left side we get:

3^2 + 4^2 = 9 + 16 = 25

and the right side:

5^2 = 25

Then we have the same in both sides, this means that these are Pythagorean triples.

2) 8, 15, 17

We must have that:

8^2 + 15^2 = 17^2

Solving the left side we have:

8^2 + 15^2 = 64 + 225 = 289

And in the right side we have:

17^2 = 17*17 = 289

So again, we have the same result in both sides, which means that these numbers are Pythagorean triples

4 0

2 years ago

SOMEONE HELP ME PLEASE ILL GIVE BRAINLY

e-lub [12.9K]

Answer:

Step-by-step explanation:

In order to determine the information you're being asked for, you need to complete the square on that quadratic. The first step is to move the constant over to the other side of the equals sign:

$x^2-2x=3$

Here would be the step where, if the leading coefficient isn't a 1, you'd factor it out. But ours is a 1, so we're good there. Now take half the linear term (the term with the single x on it), square it, and add it to both sides. Our linear term is a -2. Half of -2 is -1, and -1 squared is +1. We add +1 to both sides giving us this:

$x^2-2x+1=3+1$

Now we'll clean it up a bit. The right side becomes a 4, and the left side is written as its perfect square binomial, which is the whole reason we did this. That binomial is

$(x-1)^2=4$ (set equal to the 4 here). Now we'll move the 4 back over and set the whole thing back equal to y:

$y=(x-1)^2-4$

From this it's apparent what the vertex is: (1, -4),

the axis of symmetry is x = 1, and

the y-intercept is found by setting the x's equal to 0 in the original equation and solving for y. So the y-intercept is (0, -3).

Your choice for the correct answer is the very last one there.

8 0

3 years ago