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2 years ago

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the original price of a sweater is d dollars. you buy the sweater for (m - 3) dollars. you decorate the sweater and sell it for

(5m - 7) dollars. write an expression that represents your earnings from buying and selling the sweater

1 answer:

lora16 [44]2 years ago

7 0

Answer:

-10d

Step-by-step explanation:

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Being timed please help

Dafna1 [17]

Number 4 is arithmetic explicit

Number 1 is arithmetic recursive

Number 2 is geometric explicit

Number 3 isgeometric recursive

6 0

2 years ago

Can someone help with this math problem? 3 (x+6) = 27

Ainat [17]

Answer:

x = 3

Step-by-step explanation:

Use distributive property: a(b +c) =(a*b) + (a*c)

3(x + 6) = 27

3*x + 3*6 = 27

3x + 18 = 27 {Subtract 18 from both sides}

3x + 18 -18 = 27 - 18

3x = 9 {Divide both sides by 3}

3x/3 = 9/3

x = 3

7 0

2 years ago

Mrs. Cooper has 51.2 pounds of soil. She uses 12.9 pounds of soil for her houseplants and 30.4 pounds of soil for her garden How

myrzilka [38]

Answer:

7.9

Step-by-step explanation:

She has a total of 51.2 and uses 12.9+30.4.

The equation would be 51.2-(12.9+30.4).

51.2-(12.9+30.4)

=51.2-43.3

=7.9

Have a nice day!!!!!!! :-)

<u>KA</u>

3 0

2 years ago

Which of the following sets are subspaces of R3 ?

Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

$\to A={(x,y,z)|3x+8y-5z=2} \\\\\to for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)$

The set A is not part of the subspace $R^3$

for point B:

$\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0$

$\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon B$

The set B is part of the subspace $R^3$

for point C: $\to C={(x,y,z)|x$

In this, the scalar multiplication can't behold

$\to for (-2,-1,2) \varepsilon C$

$\to -1(-2,-1,2)= (2,1,-1)$ ∉ C

this inequality is not hold

The set C is not a part of the subspace $R^3$

for point D:

$\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)$

The scalar multiplication s is not to hold

$\to for (-4, 1,2)\varepsilon D\\\\\to -1(-4,1,2) = (4,-1,-2)$ ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace $R^3$

For point E:

$\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\$

The $x_1, x_2$ is the arbitrary, in which $ax_1+bx_2$ is arbitrary

$\to a(x_1,0,0)+b(x_2,0,0) \varepsilon E$

The set E is the part of the subspace $R^3$

For point F:

$\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon F \\\\\to a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))$

The $x_1, x_2$ arbitrary so, they have $ax_1+bx_2$ as the arbitrary $\to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F$

The set F is the subspace of $R^3$

5 0

2 years ago

write a word problem that can be solved using a system of two linear equations. solve the problem and give the meaning of the an

dmitriy555 [2]

Answer:

The sum of two numbers is 25. One of the numbers exceeds the other by 9. Find numbers

<h3>here</h3>

the other number = x + 9

Let the number be x.

Sum of two numbers = 25

According to question, x + x + 9 = 25

⇒ 2x + 9 = 25

⇒ 2x = 25 - 9

⇒ 2x = 16

⇒ 2x/2 = 16/2

⇒ x = 8

Therefore, x + 9 = 8 + 9 = 17

Therefore, the two numbers are 8 and 17.

5 0

2 years ago

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