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mrs_skeptik [129]
3 years ago
8

2(y-5)=(3y-2) can’t solve it

Mathematics
2 answers:
madreJ [45]3 years ago
4 0
Hey :)

y = -8

Use the distributive property to multiply 2 by y−5
2y−10 = 3y−2


Subtract 3y from both sides
2y −10 −3y = −2

Combine 2y and −3y to get −y
−y −10 = −2

Add 10 to both sides
−y = −2 + 10

Add −2 and 10 to get 8
−y = 8

Multiply both sides by −1
y = −8


Hope this helps!
GaryK [48]3 years ago
3 0

Answer:

y=-8

Step-by-step explanation:

2(y-5)=(3y-2)

2y-10=3y-2

-8=y

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Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data
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Based on the information represented by the boxplot ;

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  • Kayla's median is between 200 and 300

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1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

  • The minimum value is denoted by the starting position of the lower whisker on a boxplot.

  • Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

  • 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

  • 50% of sales made by Kayla is between 200 and 300

  • With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

  • The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

  • IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

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<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

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  • Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

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