Answer:
f(3) = 216
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 6ˣ
x = 3
<u>Step 2: Evaluate</u>
- Substitute: f(3) = 6³
- Exponents: f(3) = 216
Answer:
Step-by-step explanation:
The straight line equation is:
y = m*x + b Where m is the slope of the line and b the intercept with y-axis, in our case y is the depth of the tank and x (time in lapsus of 3 hours).
The slope m = ( y₂ - y₁ ) / (x₂ - x₁)
We have point A ( 3 , 8 ) and point B ( 6 , 7 )
m = ( 6 - 3 ) / (7 - 8 ) m = -3
We see that each 3 hours time-depth decreases 1 in.
Then to find the depth at the beginning of x-axis
At noon 12 tank was 9 inches, three hours before at 9 in the morning the depth was 10 inches and:
9 in the morning 10
6 in the morning 11
3 in the midnight 12
12 in the night 13
Then 13 is the intercept with y-axis
then the equation is:
h = - 3*x + 13
Note x is time in lapsus of 3 hours
I think this is the answer :)
Answer:
3.1%, dependent event
Step-by-step explanation:
We have that vowel are 5, it is from A, E, I, O, U therefore the probability of drawing a vowel is:
5/26
since there are a total of 26 options to choose from. Then, when selecting that, we are left with 25 options and 4 vowels, therefore the probability would be:
4/25
Therefore the final probability is:
5/26 * (4/25) = 0.031
In other words, selecting a vowel and then another (without replacement) the probability is 3.1%
The events are dependent, since the first event affects the second event, since the number of vowels and the number of total options are reduced.
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
