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marin [14]
3 years ago
12

Please differentiate this problem

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0

Answer:

dy/dx = d/dx sin(x-3/x+2)

dy/dx = cos(x-3/x+2) . d/dx (x-3/x+2)

dy/dx = cos(x-3/x+2) . (x + 2 - x + 3)/(x+2)²

dy/dx = [5cos(x-3/x+2)]/(x + 2)²

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Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
2 years ago
What is 1 and 1/2 worth
koban [17]
1 is a whole and 1/2 is just a fraction

4 0
3 years ago
Given the equation 5 + x - 14 = x - 7.
Yanka [14]

Answer:

x=0

Step-by-step explanation:

combine like terms on both sides of the equal sign

-9+x= x-7

move similar terms to the same side

-2=0x

divide both sides by x

x=0

7 0
3 years ago
Please help me out with this question please!!!
bixtya [17]

Answer:

3 days

Step-by-step explanation:

company A would have the equation 50x+40 =y  and company B would be 30x + 100 =y. we're tying to find the days that these cost the same so you would do 50x+40 = 30+100. When you isolate x you get 3

7 0
2 years ago
The courtyard behind jennies house is shaped like a trapaziod. The base mesures 8 meters and 15 meters.The height of the trapazo
77julia77 [94]
Formula for trapezoid area is A=b1+b2 x heightx 1/2 so your answer would be 161m squared
7 0
3 years ago
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