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3 years ago

Please differentiate this problem

Mathematics

1 answer:

strojnjashka [21]3 years ago

5 0

Answer:

dy/dx = d/dx sin(x-3/x+2)

dy/dx = cos(x-3/x+2) . d/dx (x-3/x+2)

dy/dx = cos(x-3/x+2) . (x + 2 - x + 3)/(x+2)²

dy/dx = [5cos(x-3/x+2)]/(x + 2)²

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Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

7 0

2 years ago

What is 1 and 1/2 worth

koban [17]

1 is a whole and 1/2 is just a fraction

4 0

3 years ago

Given the equation 5 + x - 14 = x - 7.

Yanka [14]

Answer:

x=0

Step-by-step explanation:

combine like terms on both sides of the equal sign

-9+x= x-7

move similar terms to the same side

-2=0x

divide both sides by x

x=0

7 0

3 years ago

Please help me out with this question please!!!

bixtya [17]

Answer:

3 days

Step-by-step explanation:

company A would have the equation 50x+40 =y and company B would be 30x + 100 =y. we're tying to find the days that these cost the same so you would do 50x+40 = 30+100. When you isolate x you get 3

7 0

2 years ago

The courtyard behind jennies house is shaped like a trapaziod. The base mesures 8 meters and 15 meters.The height of the trapazo

77julia77 [94]

Formula for trapezoid area is A=b1+b2 x heightx 1/2 so your answer would be 161m squared

7 0

3 years ago