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Alika [10]
3 years ago
5

The system of equations y = negative one-half x + 4 and y = 2x – 1 is shown on the graph below. According to the graph, what is

the solution to this system of equations? (2, 3) (3, 2) (–1, 4) (4, –1)

Mathematics
1 answer:
dimaraw [331]3 years ago
8 0

Answer:

(2, 3 )

Step-by-step explanation:

The solution to a system of equations given graphically is at the point of intersection of the 2 lines.

point of intersection = (2, 3 ) ← is the solution

You might be interested in
The cost of 4 notebooks and 3 pens is $14.50. The cost of 5 notebooks and 6 pens is $21.50. Part A: What is the cost of each ite
White raven [17]

Answer:

notebook: $2.5

pen: $1.5

part B, he can buy 3 pens

Step-by-step explanation:

A

let the cost of notebook be n, cost of pen be p

1. 4n + 3p = 14.5

2. 5n + 6p = 21.5

by 1, you can get 3p = 14.5 - 4n, put it into 2

5n + 2(14.5 - 4n) = 21.5

5n + 29 - 8n = 21.5

3n = 29 - 21.5 = 7.5

n = 2.5

put n = 2.5 into 1

4(2.5) + 3p = 14.5

3p = 4.5

p = 1.5

B

Waseem buy 3 notebooks for each pen, let number of pen be m, then the number of notebook will be 3m

m(2.5) + 3m(1.5) < 27

2.5m + 4.5m = 7m < 27

m < 27/7

maximum integer value for m = 3

6 0
2 years ago
If WXY is equilateral and WZY is<br> isosceles, find each missing measure.
timurjin [86]

Answer:

m∠1 = 60°

m∠2 = m∠4 = 39°

m∠3 = m∠5 = 21°

Step-by-step explanation:

ΔWXY is a equilateral angle,

Therefore, all angles of the the triangle are equal in measure.

m∠W + m∠X + m∠Y = 180°

3m∠W = 180°

m∠W = 60°

Since, ΔWZY is an isosceles triangle,

m∠3 = m∠5

m∠3 + m∠Z + m∠5 = 180°

m∠3 + 138° + m∠3 = 180°

2m∠3 = 180 - 138

m∠3 = 21°

Therefore, m∠3 = m∠5 = 21°

Since, m∠2 + m∠3 = 60°

m∠2 = 60 - 21

        = 39°

Since, m∠4 + m∠5 = 60°

m∠4 = 60 - 21

        = 39°

m∠1 = 60°

7 0
2 years ago
Read 2 more answers
If the 7th of an AP is equal to 11 times the 11th term, find the 18th term
Zina [86]

Answer:

-33 or 33

Step-by-step explanation:

The seventh term of an AP is written as:

a + 6d

The eleventh term of an AP is written as:

a + 10d

If the 7th term is 11 times the 11th term, then;

a + 6d = 11(a + 10d)

Expand to get:

a + 6d = 11a + 110d

11a - a = 6d - 110d

10a =  - 104d

\frac{a}{d}  = -   \frac{104}{10}

\frac{a}{d}  = -   \frac{52}{5}

We must have a=-52 and d=5

Or

a=52 and d=-5

For the first case, the 18th term is :

- 52 + 5 \times 17 = 33

For the second case,

52 - 5 \times17 =  - 33

3 0
3 years ago
Quick help please i can’t
VladimirAG [237]

Dont say you can't! I believe in youu!


6 0
3 years ago
HELPPP MEEE PLEASE !!!!
zimovet [89]
The answer to the question is C.
8 0
3 years ago
Read 2 more answers
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