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Hunter-Best [27]
3 years ago
13

When you are factoring a trinomial with a leading coefficient other than 1, which would be the best thing to do first?

Mathematics
1 answer:
Alchen [17]3 years ago
4 0

Answer:


Step-by-step explanation:

 c. Look for a common factor in each term.

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Practice multiplying numbers by powers of 10.
Juliette [100K]
Answer:

Multiply (400 + 20 + 3) x 10000

Add 4 zeros to the end of 423

Step-by-step explanation:

423 x 10,000 = Adding the amount of zero’s in 10000 to 423



8 0
3 years ago
The 18 faculty members in a college math department range in age from 32 to 68. A stem plot follows: The first and third quartil
valentina_108 [34]

Answer:

Q_{1}=39, \:and\: Q_{3}=58

Step-by-step explanation:

1) This Stem and Leaf plot works like a Histogram. Completing the question, check below the Stem plot. Look the data out of the Stem plot and within (in the graph below)

32, 34 , 38 , 39 , 39 , 40 , 43 , 45 , 46 , 49 , 53 , 54 , 57 , 58 , 59 , 59 , 63 , 68

2) Notice how the first digit is on the Stem column (check below)

3) To find the first and Third Quartiles

Let's use the formulas to find the position, then the value. As it follows:

Q_3=\frac{3}{4}(n+1) \Rightarrow  Q_3=\frac{3}{4}(18+1) Q_3=14.25 \approx14th =58

Q_1=\frac{(n+1)}{4} \Rightarrow Q_1=4.75 th \approx Q_1 =5th =39

4 0
3 years ago
What is 865 divided by 40
Nutka1998 [239]
21.625 is your answer to 865/40
5 0
3 years ago
Write a x (-a)x 13 x a x (-a) x 13 in power notation
miss Akunina [59]

Answer:

a\times (-a)\times 13\times a\times (-a)\times 13 can be written in power notation as a^{4}\times 13^{2}

Step-by-step explanation:

The given expression

a\times (-a)\times 13\times a\times (-a)\times 13

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:

Let

a\times (-a)\times 13\times a\times (-a)\times 13

= [13\times13][(a\times (-a)\times a\times (-a)]

As

13\times13 = 13^{2} , a\times a = a^{2} , (-a)\times (-a) = (-a)^{2}

So,

=[13^{2}][a^2\times (-a)^2]

As

(-a)^2 = a^{2}

So,

=[13^{2}][a^2\times a^2]

As ∵a^{m} \times a^{n}=a^{m+n}

=[13^{2}][a^{2+2}]

As ∵a^{m} \times a^{n}=a^{m+n}

=13^{2}\times a^{4}

=a^{4}\times 13^{2}

Therefore, a\times (-a)\times 13\times a\times (-a)\times 13 can be written in power notation as a^{4}\times 13^{2}

<em>Keywords: power notation</em>

<em>Learn more about power notation from brainly.com/question/2147364</em>

<em>#learnwithBrainly</em>

5 0
3 years ago
1. En una tienda de ropa se pusieron en oferta guantes y chamarras. El primer dia se vendieron 6 pares
Softa [21]
10560 so much money all forget to count
6 0
2 years ago
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