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3 years ago

When you are factoring a trinomial with a leading coefficient other than 1, which would be the best thing to do first?

Mathematics

1 answer:

Alchen [17]3 years ago

4 0

Answer:

Step-by-step explanation:

c. Look for a common factor in each term.

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Find the y value for the point that divides the line segment CD into a ratio of 4:1.

7nadin3 [17]

Answer:

We also drew a graph with 2 examples.

Step-by-step explanation:

If we have the line segment CD, we can divide it by 4: 1 as follows:

If point C has the coordinates (x1, z1) and point D has the coordinates (x2, z2), we calculate coordinate the points Y as follows:

y1 = (x2-x1) · 4/5

y2 = (z2-z1) · 4/5

In this way we have obtained the point Y with the coordinates (y1, y2), and the point Y divides the line segment CD by 4:1.

We also drew a graph with 2 examples.

3 0

3 years ago

PLEASE HELPTH ME (MODERATORS STOP I REPEAT STOP REMOVING MY QUESTIONS BRO)

kompoz [17]

Answer:

X=75

Y=110

Step-by-step explanation:

A straight line is 180, so add the equations that make a line and set them equal to 180

x+20+x+10=180

Combine like terms

2x+30=180

Subtract 30 from both sides

2x=150

Divide by 2

X=75

Same for y

y+y-40=180

2y-40=180

Add 40 to both sides

2y=220

Divide by 2

Y=110

5 0

3 years ago

There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0

2 years ago

Which answer is the most reasonable estimation? Lance is organizing his baseball card collection into albums. Each album can hol

RSB [31]

Hello there.

Which answer is the most reasonable estimation? Lance is organizing his baseball card collection into albums. Each album can hold up to 50 cards. He has 202 cards in his collection. About how many albums will Lance need? A. about 5 B. about 10 C. about 50 D. about 150

Answer: A) 5

8 0

3 years ago

Read 2 more answers

Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th

xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is $\bold{W=-3e^{7x}}$

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

$W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|$

Thus replacing the functions of the exercise we get:

$W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|$

Working with the determinant we get

$W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}$

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0

3 years ago