Answer:
![\left[\begin{array}{cccc}1&3&4&5\&3&1&5&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%263%264%265%5C%263%261%265%266%5Cend%7Barray%7D%5Cright%5D)
The only ones are on the "diagonal", where i = j. Else the position is simply the sum.
Answer:
19/24
Step-by-step explanation:
z-2/3=1/8
z=2/3+1/8
z=19/24
Answer:
the probability of a Type I error is 0.10
Step-by-step explanation:
Given the data in the question;
significance level ∝ = 0.10
Null H₀ hypothesis is true;
the probability of a Type I error = ?
we know that; a type 1 error is the error of rejecting a Null hypothesis when in reality, it is true. That is false positive.
Hence, our type 1 error will be;
P(rejecting null | null true ) = significance level ∝ = 0.10
Therefore, the probability of a Type I error is 0.10
Answer:
Step-by-step explanation:
h=7mm
