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2 years ago

Construa a matriz B=(bij)2×4 definida por Bij= 1, se i=j i+j, se i≠j

Mathematics

1 answer:

Alexandra [31]2 years ago

4 0

Answer:

$\left[\begin{array}{cccc}1&3&4&5\&3&1&5&6\end{array}\right]$

The only ones are on the "diagonal", where i = j. Else the position is simply the sum.

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HELP

daser333 [38]

Answer:

cos

Step-by-step explanation:

take 31 degree as reference angle

using cos rule

cos 31=adjacent/hypotenuse

0.85=14/x

x=14/0.85

x=16.47

x=16.5

8 0

3 years ago

Read 2 more answers

CAN SOMEONE HELP, PLEASE?

Marizza181 [45]

Answer:

see below

Step-by-step explanation:

The answer choices all start with ΔYHB. The first two letters (YH) identify the longest leg, and the right-angle vertex (H) is named second.

Using this same naming convention, the other two right triangles in the figure are ...

ΔYDH and ΔHDB

The similarity statement identifying these triangles as being similar is the one shown below.

3 0

4 years ago

1. A triangle inscribed in a semicircle can be identified as a/an _______ triangle.

Mumz [18]

Answer:

B. right

Step-by-step explanation:

Assuming one side of the triangle is the diameter of the semicircle, the triangle will always be a right triangle. (This is a useful fact to remember.)

7 0

3 years ago

Jason placed a mirror on the ground 40 feet from the base of the tree. He walks backwards until he can see the top of the tree i

Nady [450]

Well how many feet is he from the image

3 0

3 years ago

Read 2 more answers

a. Suppose we had $15,192 cash and invested it in the bank at 16 percent interest, how much would you have at the end of 1, 2, 3

Goryan [66]

Answer:

Part a) $\$17,622.72$

Part b) $\$20,442.36$

Part c) $\$23,713.13$

Part d) $\$27,507.23$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) How much would you have at the end of 1 year?

in this problem we have

$t=1\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*1}=\$17,622.72$

Part b) How much would you have at the end of 2 year?

in this problem we have

$t=2\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*2}=\$20,442.36$

Part c) How much would you have at the end of 3 year?

in this problem we have

$t=3\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13$

Part d) How much would you have at the end of 4 year?

in this problem we have

$t=4\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23$

5 0

3 years ago

Construa a matriz B=(bij)2×4 definida por Bij= 1, se i=j i+j, se i≠j​

Construa a matriz B=(bij)2×4 definida por Bij= 1, se i=j i+j, se i≠j