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frutty [35]
3 years ago
5

I NEED HELP RIGHT NOW PLS!!

Mathematics
2 answers:
Zarrin [17]3 years ago
6 0

Answer:

I think the answer is 2 because 2.5 x 2 = 5.

I'm sorry if this is wrong, I'm a bit unsure.

Step-by-step explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

Genrish500 [490]3 years ago
6 0

Answer:

2

Step-by-step explanation:

we simply divide 2 1/2 from 5

5÷2 1/2

5÷5/2

5×2/5

2(we cancel five)

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Answer:

swap the bottom two. it should be, in this order, 32+c, 0.25, 8, 0.25c

Step-by-step explanation:

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Points W X and y are collinear (that is on the same line). Write and solve an equation to find m
AleksAgata [21]

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I think it's x=180*-117*

Step-by-step explanation:

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Jane will draw one card from the regular deck of 52 cards. In how many ways can she choose a jack or a black card?
elena-s [515]

Answer:

28

Step-by-step explanation:

In a regular 52 card deck, 26 are black (clubs or spades).  Additionally, there are two red jacks (diamonds and hearts).  This equals 28/52.  As a probability, it would be 28/52=14/26=7/13.  This could also be expressed as a percentage or decimal.  0.538 or 53.8%.  But the question asks <em>how many ways</em> can she choose a jack or black card, so I’m assuming they don’t want the probability, just the number, which is 28.

3 0
3 years ago
Read 2 more answers
Activity 3
skad [1K]

Answer:

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Step-by-step explanation:

60-3=57\\\\57/3=19

3 0
2 years ago
Read 2 more answers
find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)
frutty [35]

Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

8 0
3 years ago
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