4x + 6 - 2x = x + 3 + 10, solve for x.

Mathematics

1 answer:

Marizza181 [45]3 years ago

7 0

4x+6-2x = x+3+10

COMBINE LIKE TERMS

2x+6= x+13
-x -x.

x+6=13
-6 -6

x=7 is your answer.

You might be interested in

Factor the expression. 12p + 60 [?1(p + [ D)

zhenek [66]

Answer:

$12p+60$ $= 12(p + 5)$

Step-by-step explanation:

Given

$12p+60$

Required

Factor

$12p+60$

Express $12p$ as $12 * p$ and $60$ as $12 * 5$

So, we have:

$12p+60$ $= 12 * p + 12 * 5$

Apply distributive property

$12p+60$ $= 12(p + 5)$

8 0

3 years ago

Solving 12-(x+3)=10

Margarita [4]

12-(x+3)=10

Simplify the equation.

12-x-3=10

Combine like terms.

(12-3)-x=10

Simplify.

9-x=10

Subtract 9 from both sides to get x by itself.

-x=1

Divide both sides by -1 to get x by itself.

x=-1

~Hope I helped!~

4 0

4 years ago

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

Left part:

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$