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Dovator [93]
3 years ago
6

3-x/4>2 plz help me!!!

Mathematics
1 answer:
Vesnalui [34]3 years ago
7 0
3 -x/4 > 2
⇒ -x/4 > 2-3
⇒ -x/4 > -1
⇒ -x >  -1*4
⇒ -x > -4
⇒ x < 4
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pantera1 [17]

Answer:

2<∛13<3      1<∛6<2

Step-by-step explanation:

Lets find the integers a and b  ∛13 lies between.

a<∛13<b

a³<13<b³

=> a=2 so 2³=8   and b=3 so 3³=27    8<13<27

Similarly     a<∛6<b

a³<6<b³

a=1    and b=2

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S = R-rR solve for R
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Answer:

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Step-by-step explanation:

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2 years ago
In the given figure △ABC ≅△DEC. Which of the following relations can be proven using CPCTC ?
Serhud [2]

Option B:

\overline{A B}=\overline{D E}

Solution:

In the given figure \triangle A B C \cong \triangle D E C.

If two triangles are similar, then their corresponding sides and angles are equal.

By CPCTC, in \triangle A B C \ \text{and}\ \triangle D E C,

\overline{AB }=\overline{DE} – – – – (1)

\overline{B C}=\overline{EC} – – – – (2)

\overline{ CA}=\overline{CD} – – – – (3)

\angle ACB=\angle DCE  – – – – (4)

\angle ABC=\angle DEC  – – – – (5)

\angle BAC=\angle EDC  – – – – (6)

Option A: \overline{B C}=\overline{D C}

By CPCTC proved in equation (2) \overline{B C}=\overline{EC}.

Therefore \overline{B C}\neq \overline{D C}. Option A is false.

Option B: \overline{A B}=\overline{D E}

By CPCTC proved in equation (1) \overline{AB }=\overline{DE}.

Therefore Option B is true.

Option C: \angle A C B=\angle D E C

By CPCTC proved in equation (4) \angle ACB=\angle DCE.

Therefore \angle A C B\neq \angle D E C. Option C is false.

Option D: \angle A B C=\angle E D C

By CPCTC proved in equation (5) \angle ABC=\angle DEC.

Therefore \angle A B C\neq \angle E D C. Option D is false.

Hence Option B is the correct answer.

\Rightarrow\overline{A B}=\overline{D E}

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3 years ago
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