Answer:
Step-by-step explanation:
From the condition of perpendicularity, if two lines must be perpendicular to each other, the product of their gradient rather the slope must be equaled to ( -1 ).
Equation of a line ; y = mx+ c, where m1 is the gradient of the line and c us the point of intersection if the line on the y- axis.therefore, the equation
3x + 4y = 14, when re arranged, now becomes, 4y = -3x + 14, divide through by 4, gives, y = -3x/4 + 14.
Therefore, m1, = -3/4 and m2, = 4/3 going by the condition. Since the line passes through the coordinate of (2,3), where x = 2, and y = -3, then, substitute for x and y in y = mx+ c, minding the m2, to find C, therefore,
-3 = 4/3x2 + c. -3 = 8/3 +c
Multiply through by 3 to make it a linear equation,
-9 = 8 + 3c; -9 - 8 = 3c, -17= 3c
c = -17/3.Now substitute for c in the equation ,y = mx+ c, the equation now becomes, y = 4x/3 - 17/3. Therefore the new equation is
3y = -4x - 17.
) = 1/
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