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Neko [114]
4 years ago
11

List the partial products of 15 times 32

Mathematics
2 answers:
Musya8 [376]4 years ago
5 0
Hmmm... the partial products?
AURORKA [14]4 years ago
5 0
480?
do you mind answering what a partial product is?
You might be interested in
The sides of a right triangle form an arithmetic sequence with the difference d. Find the area of an inscribed circle in terms o
pantera1 [17]

Answer:

The sides of a right triangle form an arithmetic sequence with the difference is described below in detail.

Step-by-step explanation:

Let's denominate the first term aa and the obvious difference dd. Therefore, your course enhances:

a, a+d, a+2da, a+d, a+2d

Now, these three terms form the sides of a right triangle. Since a+2da+2d is the highest (considering d > 0), we can state that it is the hypothenuse.

applying the Pythagorean Theorem:

a2+(a+d)2=(a+2d)2a2+(a+d)2=(a+2d)2

a2+a2+2ad+d2=a2+4ad+4d2a2+a2+2ad+d2=a2+4ad+4d2

3d2−a2+2ad=03d2−a2+2ad=0

(3d−a)(d+a)=0(3d−a)(d+a)=0

Therefore, your solutions are

3d=a3d=a

andd=−ad=−a

So if a = 3, d = 1. Therfore, one potential  sequence is 3, 4, 5.

Similarly, if a = 6, then d = 2, so another potential sequence is 6, 8, and 10

3 0
3 years ago
I need step by step explanation for this!!
Margaret [11]
<h3>Answer:  The original number is 57</h3>

=========================================================

Explanation:

T = tens digit of original number

U = units digit of original number

"units digit" is the same as "ones digit"

The original number is in the form 10T+U. For example, let's say that T = 3 is the tens digit and U = 1 is the units digit. This means 10T+U = 10*3+1 = 31 is the original number. Though in this example, the digits don't add to 12.

To make the digits add to 12, we have the equation T+U = 12. This solves to U = 12-T which we'll use later.

--------------------

The digits are reversed to get the new number 10U+T and this is 15 times the original tens digit, so

new number = 15*(original tens digit)

10U+T = 15T

from here we plug in U = 12-T which we found earlier. This effectively eliminates or gets rid of the U variable to leave us with T only

10U+T = 15T

10(12-T)+T = 15T ..... replace U with 12-T

which we can now solve for T

--------------------

10(12-T)+T = 15T

120-10T+T = 15T

-9T+120 = 15T

120 = 15T+9T ... adding 9T to both sides

120 = 24T

24T = 120

T = 120/24 .... divide both sides by 24

T = 5

The original tens digit is T = 5

The original units digit is U = 12-T = 12-5 = 7

So the original number is 10T+U = 10*5+7 = 57

Flipping the digits gets us 75 which is 15 times that of the original tens digit of 5. The original number has its digits add to 5+7 = 12. The answer has been confirmed.

6 0
3 years ago
Read 2 more answers
Help. Picture attached.
Phoenix [80]
4) A f is continuous at x=c
5) B if f is not differentiable at x=c, then f is not continuous at x=c
5 0
3 years ago
X2+8x=-1 complete the square
Sophie [7]
(X+4)^2-15

This is the answer
6 0
3 years ago
PLEASE HELP 100 POINTS.
aalyn [17]

Wait I don’t understand what u need
3 0
3 years ago
Read 2 more answers
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