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-BARSIC- [3]
4 years ago
11

I just need to know if I did these two problems right or not because I just learned this in class today.

Mathematics
1 answer:
Serggg [28]4 years ago
5 0
Hahah yea you did man! <3 

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Amy wants to buy a pair of jeans that cost $65. Today the store is offering a straight discount of 25%. Calculate her savings an
Whitepunk [10]
Her savings is the 25% amount... well, if we take 65 to be the 100%, how much is 25% of that?

\bf \begin{array}{ccllll}&#10;amount&\%\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;65&100\\&#10;x&25&#10;\end{array}\implies \cfrac{65}{x}=\cfrac{100}{25}

solve for "x", that's her savings

the cost of the jeans is 65 - x
7 0
3 years ago
Read 2 more answers
The sum of three prime numbers is 22. What is the largest possible product of these numbers?
statuscvo [17]

Step-by-step explanation:

a+b+c=22

abc=?

2+3+17=22

2×3×17=102

3 0
3 years ago
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A $260 suit price is marked down 10 % find the sale price
NikAS [45]

Answer:

260*0.90=sales price=234

Step-by-step explanation:

3 0
3 years ago
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85.87 J or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°C
Andru [333]

Answer:

The required specific heat is 196.94 joule per kg per °C  

Step-by-step explanation:

Given as :

The heat generated = Q = 85.87 J

Mass of substance  (m)= 34.8 gram = 0.0348 kg

Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C

Let the specific heat = S

Now we know that

Heat = Mass × specific heat × change in temperature

Or, Q = msΔt

Or, 85.87 = (0.0348 kg ) × S × 12.53°C

Or , 85.87 = 0.4360 × S

Or, S = \frac{85.87}{0.4360}

∴ S = 196.94 joule per kg per °C

Hence the required specific heat is 196.94 joule per kg per °C   Answer

7 0
3 years ago
Myra took a picture of the sky one afternoon when two jet airplanes appeared to draw a pair of parallel lines with their vapor t
Dmitrij [34]
1, 3, 5 are the correct answers :)
7 0
4 years ago
Read 2 more answers
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