I WILL GIVE BRAINLY! PLEASE HELP!
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f(x) = (x + 2)² ⇒ f(x) = (x - (-2))² + 0 ⇒ h = -2 , k = 0
vertex: (-2, 0)
domain: R
range: <0, ∞)
axis of symetery: x = -2
up {a=1>0}
min: f(-2) = 0
graph: {f(0)=4}
Answer:
The roots of the given equation is x=4,3i,-3i
Step-by-step explanation:
The given cubic equation is
To find the roots we have to equate the equation to zero
ie,
It can be done by using Synthetic division method
Therfore [tex](x-1) is not a factor or root
now put x=-1
Therfore [tex](x-1) is not a factor or root
similarly let x=2,-2,3,-3 all not equal to zero so the are not roots.
let x-4 is a factor of given equation
then it satifies the equation ie (x-4) is a root
And it may be written as
[tex](x-4)(x^2+9)