Ask question

Ask question

All categories

3 years ago

14

hree different stocks were ordered. The purchase prices were 8 ⅜ dollars, 12 ⅛ dollars and 15 ⅜ dollars.how much was paid for al

l three stocks?

2 answers:

Murljashka [212]3 years ago

8 0

When you add all of the totals together your total amount will be $35.875

dybincka [34]3 years ago

5 0

8 3/8 + 12 1/8 + 15 3/8

8 + 12 + 15 = 35
3/8 + 1/8 + 3/8 = 7/8

total = 35 7/8

You might be interested in

Which equation represents the line through (0,0) and (3, 4)?

Andreas93 [3]

Answer:

<u>4-0</u>

3-0

=4/3

<u>y-0</u> =4/3

x-0

3y-0=4x-0

3y=4x

y=4/3x

Step-by-step explanation:

7 0

2 years ago

What is 3 x 2¹ ?? please help

dybincka [34]

Answer:

6

Step-by-step explanation:

Don't worry about that little one, Its just 3 x 2 = 6 the one means to multiply that number once.

7 0

3 years ago

Read 2 more answers

Complete the following multiplication problems. a. 0.34 × 6 b. 0.11 × 4 c. 17 × 0.07 d. 28 × 0.003 e. 3.8 × 5 f. 5.931 × 7 g. 14

kvasek [131]

A. 2.04
b .44
c.1.19
d .084
e. 19
f. 41.517
g.182.91
h. 96.16
i. .24
j. .0225
k. .0018
l. .00592
m.2.07
n. 2.175
o. .01359
p. 3.00552
q. 4.07
r. 71.064
s. 27.877
t. 35.7124

3 0

3 years ago

Read 2 more answers

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago

Suppose the speeds of vehicles traveling on a highway are normally distributed and have a known population standard deviation of

erik [133]

Answer:

2.88

Step-by-step explanation:

Data provided in the question

$\sigma$ = Population standard deviation = 7 miles per hour

Random sample = n = 32 vehicles

Sample mean = $\bar X$ = 64 miles per hour

98% confidence level

Now based on the above information, the alpha is

= 1 - confidence level

= 1 - 0.98

= 0.02

For $\alpha_1_2$ = 0.01

$Z \alpha_1_2$ = 2.326

Now the margin of error is

$= Z \alpha_1_2 \times \frac{\sigma}{\sqrt{n}}$

$= 2.326 \times \frac{7}{\sqrt{32}}$

= 2.88

hence, the margin of error is 2.88

5 0

3 years ago