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Alexxx [7]
2 years ago
13

Solve k^2+4k+4=25 by taking the square root of each side. Please show work, thanks

Mathematics
1 answer:
MAVERICK [17]2 years ago
8 0

Answer:

Step-by-step explanation:

k=3 or k=−7 both choices are correct

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Rewrite 14 1/3 as an improper fraction
Anastaziya [24]

Answer:

Step-by-step explanation:

((14×3) + 1 )/3 = (43/3)

5 0
3 years ago
A certain radioactive isotope has a half-life of 15 days. If one is to make a table showing the half-life decay of a sample of t
Verdich [7]
A half-life of the isotope is 15 days and at start its mass is 32 g.
A table:
              t:                 m:
              0                32 g
             15               16 g
             30                 8 g
             45                 4 g
             60                 2 g
             75                 1 g
In the first column is used an arithmetic sequence ( a 1 = 0, d = 15 ).
In the second column is used a geometric sequence ( a 1 = 32, r = 1/2 )                       
7 0
3 years ago
PLEASE HELPPP MEE.....
mariarad [96]

Answer:

C ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

6 0
2 years ago
Make a box ­and ­whisker plot of the data.<br><br> 24, 18, 29, 21, 16, 23, 13, 11
Elanso [62]
To make a box and whisker plot you must first order the data:

11, 13, 16, 18, 21, 23, 24, 29

Then find the median:

19.5

Then split the data into two sections by the median:

11, 13, 16, 18 and 21, 23, 24, 29

Now find the medians of those sets

14.5 and 23.5

With this information we can conclude Option C is the correct plot

Hope this helps!
7 0
3 years ago
Read 2 more answers
A game designer must decide how to color four buildings that are in a row. Using only the colors yellow, green, red, and blue, e
topjm [15]

Answer:

The number of ways are there to paint the four buildings is 48.

Step-by-step explanation:

I) let the first building be any color. Therefore the first building can be painted with any of the 4 colors.

Therefore the first building can be colored in 4 ways.

ii) the second building can be colored in 3 ways since it cannot be colored the

same color as the first building.

iii) the third building can also be colored in 3 ways.

iv) the last building can be colored in 2 ways because it cannot be the same color as the first building or the color of the adjacent building.

Therefore the total number of ways the buildings can be colored = 4 \times 3 \times 3  \times 2 = 48.

7 0
3 years ago
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