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Oksi-84 [34.3K]
3 years ago
12

1.11 People fit comfortably in a 5 feet by 5 feet area. Use this value to estimate the size of a crowd that is 5 feet deep on BO

TH sides of the street along a 5-mile section of a parade route.
(4 Points)
Mathematics
1 answer:
Oliga [24]3 years ago
3 0

Answer:

in 5ft by 5ft = 25ft^2, there can be 1 person

A normal street is 30ft wide

Then, if we want the width such that is 5 ft deep (from both sides)

Then we should subtract two times 5 ft:

30ft - 5ft - 5ft = 20ft.

Now the length is 5 miles

and 1 mile = 5280 ft

then 5 miles = 5*( 5280 ft) = 26,400 ft.

Then the area is:

20ft by 26,400 ft. =528,800  ft^2

And we know that in 25 ft^2 we can fit one person.

How many spaces of 25ft^2 we have in the 528,800 ft^2?

this is:

N =  528,800 ft^2/25ft^2 = 21,152

This means that in the street 21,152 people can fit comfortably.

The size of the crowd is  21,152 people.

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y = 3x - 8

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What is an itrational number between 5 and 7
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How do you get the equation of the line in fully simplified slope-intercept form?​
Igoryamba

Answer:

y= -2/5 x -4

Step-by-step explanation:

So the equation is y=mx+b. Where m=slope and b=y-intercept. To find b, you would see at what point does the line cross the y axis. That would be at -4 so, -4 would be the b or y-intercept. To find m, you would take two points on the line and use this equation:

m=(y2 - y1 )/(x2 - x1)

If you were using the points, (-10,0) and (0, -4) the equation would be:

m=(-4-0) / (0+10)

So, m= -2/5

The equation of the line would end up being:

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4 0
3 years ago
If Luke pushes his sister in a wagon down the driveway that is 14 meters long and it takes 22 Newtons of force, how much work di
erica [24]

Hello!

The answer is:

Luke did a work of 308N.m or 308 Joules.

<h2>Why?</h2>

When a force is applied on a object making it to move covering a distance we call it "work". The movement caused by the force, will follow the same direction that the force.

We can calculate the work done by using the following equation:

Work=Force*distance*Cos(\alpha)

Where,

Work is the transferred energy.

Force, is the force applied to the object.

Distance, is the distance covered due to the applied force.

α, is the angle at the work is done.

We are given the following information to calculate the work done:

Force=22N\\Distance=14m

So, substituting the given information into the equation to calculate work, we have:

Work=Force*distance\\Work=22N*14m=308N.m

Hence, we have that Luke did a work of 308N.m or 308 Jouls.

Have a nice day!

3 0
3 years ago
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