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Oksi-84 [34.3K]
2 years ago
12

1.11 People fit comfortably in a 5 feet by 5 feet area. Use this value to estimate the size of a crowd that is 5 feet deep on BO

TH sides of the street along a 5-mile section of a parade route.
(4 Points)
Mathematics
1 answer:
Oliga [24]2 years ago
3 0

Answer:

in 5ft by 5ft = 25ft^2, there can be 1 person

A normal street is 30ft wide

Then, if we want the width such that is 5 ft deep (from both sides)

Then we should subtract two times 5 ft:

30ft - 5ft - 5ft = 20ft.

Now the length is 5 miles

and 1 mile = 5280 ft

then 5 miles = 5*( 5280 ft) = 26,400 ft.

Then the area is:

20ft by 26,400 ft. =528,800  ft^2

And we know that in 25 ft^2 we can fit one person.

How many spaces of 25ft^2 we have in the 528,800 ft^2?

this is:

N =  528,800 ft^2/25ft^2 = 21,152

This means that in the street 21,152 people can fit comfortably.

The size of the crowd is  21,152 people.

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Please help. A rectangle's length and width are in a ratio of 7:3. The area is 84 square feet. What are the
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Answer:

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Step-by-step explanation:

A = 84 feet square

ratio of length and width = 7 : 3

total ratio of length and width 10 = a

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width = (3/10)a

A = length x width = (7/10)a x (3/10)a = (21/100)a² = 84

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3 0
3 years ago
There are 12 inches in 1 foot and 5,280 feet in 1 mile. Jada ran 34 miles.
zvonat [6]

For this case we must convert 34 miles to feet and inches.

34 miles to feet:

34 miles * \frac {5280} {1} * \frac {feet} {miles} = 179,520 feet

Jada runs 179,520 feet

34 miles to inches:

34 miles * \frac {5280} {1} * \frac {feet} {miles} * \frac {12} {1} * \frac {inches} {foot} = 2,154,240 inches

Jada runs 2,154,240 inches

Answer:

Jada ran 179,520 feet

Jada ran 2,154,240 inches

3 0
2 years ago
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