Answer:
No, we cannot conclude anything about 0.10
Yes, they have made the same decision.
Step-by-step explanation:
Consider the provided information.
Part (A)
They based this conclusion on a test using α = 0.05. Would they have made the same decision at α = 0.10
A significance level of 0.05 indicates a 5% risk of concluding that a difference exists
From the normal table the critical value is Z(0.05) = 1.645 and we accept null hypothesis.
If α = 0.1, the critical value is Z(0.1)=1.28
1.28 is less than 1.645.
Therefore, we cannot conclude anything about 0.10
Part (B)
α = 0.01, the critical value is Z(0.01)=2.33
The critical value of α = 0.05 is 1.645 which is less than 2.33,
So we would again reject the null hypothesis.
Hence, they have made the same decision.
60% is her score as a percentage
To solve this problem, you'll need to subtract 25 (total quantity of roasted almonds) by the remaining variable of roasted almonds (3 1/2 lbs.), resultant towards finding how many pounds of roasted almonds Xavier had sold; Xavier had sold 21 1/2 pounds of almonds.
Step 1
Find the volume of a sink
Volume sink=(4/6)*pi*r³ (half-sphere)
Diameter=20 in--------------> r=D/2-----------> r=10 in
Volume sink=(4/6)*pi*10³---------> (2000/3)*pi in³ --------> 2093.33 in³
(a) What is the exact volume of the sink?
the answer part a) is (2000/3)*pi in³ (2093.33 in³)
(b) One conical cup has a diameter of 8 in. and a height of 6 in. How many cups of water must Ki’von scoop out of the sink with this cup to empty it?
volume of a conical cup=pi*r²*h/3
diameter=8 in--------------> r=4 in
h=6 in
volume of a conical cup=pi*4²*6/3-----------> 32*pi in³
if one cup---------------------> 32*pi in³
X---------------------------> (2000/3)*pi in³
X=(2000/3)*pi/(32*pi)------------> 20.83----------> 21 cups
the answer part b) is 21 cups
(c) One cylindrical cup has a diameter of 4 in. and a height of 6 in. How many cups of water must he scoop out of the sink with this cup to empty it?
volume of a cylindrical cup=pi*r²*h
diameter=4 in--------------> r=2 in
h=6 in
volume of a cylindrical cup=pi*2²*6-----------> 24*pi in³
if one cup---------------------> 24*pi in³
X---------------------------> (2000/3)*pi in³
X=(2000/3)*pi/(24*pi)------------> 27.77----------> 28 cups
the answer part c) is 28 cups
Answer: No, the page content of the atlas cannot be replicated on the eReader.
Please check explanations below for solution to question (b)
Step-by-step explanation: The dimensions of the eReader screen is given as 8 inches by 6 inches. In order to move a rectangular shape such as the atlas onto it would require the same measurements or, a measurement that has the same ratio as both the length and width of the screen, but a reduced size.
This brings us to similar shapes. When two shapes (rectangles in this case) are similar, it simply means there is a common ratio between the corresponding sides, that is the length and the width. If rectangle 1 has its side measuring 8 inches, then rectangle 2 would have the corresponding side having a common ratio with that of rectangle 1. This means the corresponding side in rectangle 2 can either be an enlargement (which would mean 8 times a scale of enlargement) or a reduction (which means 8 divided by a scale of reduction).
In the question given, the eReader screen has dimensions of 8 inches by 6 inches. The atlas has dimensions given as 19 inches by 12 inches. By observation we can see that the width of the atlas is times 2 of the screen. The length of the atlas however is not times 2 of the screen. That is;
Ratio = Rectangle 1 : Rectangle 2
Ratio of Width = 6 : 12
Ratio of Width = 1 : 2
Likewise
Ratio of Length = 8 : 19
Ratio of Length ≠ 1: 2
This proves that the atlas cannot be scaled down to fit properly into the screen. A solution to make this possible would be to resize the length of the atlas to become times 2 of the eReader screen. This would result in the atlas having new dimensions given as
Length = 16 inches
Width = 12 inches
This would ensure that both rectangular shapes are similar and the atlas can now be scaled down by a factor of 2 to fit in properly into the eReader screen.