Answer:
x/i=22
Step-by-step explanation:
x/33=2/3*i
*33 *33
x=2/3*33*i
/i /i
x/i=2/3*33
x/i=22
This question not incomplete
Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
domain(-8. -2. 1 4
range( -10 0 10 0
and the the given exp is function
Answer
18(2)+12(2)-4(5)
36+24-20
60-20
40
Step-by-step explanation:
since they had two-18 yard passes and two 12 yard runs, that's the first part of the expression, and then they had four penalties that cost them 5 yards, and that was the last term. When you simplify, you end up with 40 yards gained.
In math
Passes: 18(2)
Runs: 12(2)
Penalties:4(5)
equation
18(2)*12(2)-4(5)
Hope it helped
