Answer: Mine is like that a well, It's just notification overall ain't nobody messaging you.
25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
25, because a cube that is 10x10 would have an area of 100. and the cubes that are 2x2 would have an area of 4. so you take 100 and divide it by 4. answer is 25.
Answer:
$49.60
Step-by-step explanation:
The equation setup I used for this was as follows: $16 x (112/36)
Using PEMDAS, you'd start with the division part, 112/36. Although, I did this a bit differently, and being a bit further in school, I don't know if you go through this where you're at.
Start by factoring 112 into 4(28). This leaves you with 4(28)/36.
Next, cancel 4 out of 36. Since 4 is the common factor in 28 and 36, you cancel the four out of the equation, leaving you with 28/9. Convert this to its decimal form, 3.1.
Finally, take the 3.1 and multiply that by $16, which comes out to $49.60.
Answer:
∠x = 67°
Step-by-step explanation:
∠x = 67° because they both are inscribed angles of the same arc
