The picture below has both of the answers to your problem.
Well whats theproblem so we can figure it out?
The triangle in the drawing is semi equilateral. Therefore a=√(14^2-7^2)=12.12 cm
The base of a regular pyramid consists of 6 equilateral triangles. The area of each triangle is: (14*12.12)/2 = 84.87 cm^2
The base: 6*84.87=509.22 cm^2
Answer:
∠p and ∠s; ∠q and ∠r [ both triangles are similar, the second triangle is smaller version of the other triangle and tilted right ]
