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My name is Ann [436]
3 years ago
14

Who wants free brainlist

Mathematics
2 answers:
Dahasolnce [82]3 years ago
4 0

Answer:

That would be nice.

Step-by-step explanation:

If you could :)

Kobotan [32]3 years ago
4 0

Answer:

i do

Step-by-step explanation:

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Help please... extra points
True [87]

5 * 7 = 35. App. 35 meatballs will be eaten.

12 + 12 + 12 = 36.

If he wants to have enough meatballs for everyone at the party, he needs to thaw out 3 pounds of hamburger meat.

5 0
3 years ago
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To win a certain state lottery, players must correctly choose 4 numbers (in any order) from the numbers 1 to 40. How many differ
inn [45]
Theres about 800 different combinations, i'm not sure though, i'm sorry if i'm wrong
4 0
3 years ago
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Five less than the product of 14 and carlos's age
lesya [120]
Is this the full question that is stated?

6 0
3 years ago
Bject?
Yakvenalex [24]

Answer:

The entire volume would be 60m, but if it's talking only about the little rectangle on top then the answer is 6m.

Step-by-step explanation:

The length of the smaller object is 1m, the height is 2m, and the width is 3m (as seen to the right side near the bigger block).

Multiply all those numbers together (1×2=2, 2×3=6 or just simply 1×2×3=6)

5 0
2 years ago
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Solve the following equation by completing the square. 3x^2-3x-5=13
mr Goodwill [35]

we'll start off by grouping some

\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}

6 0
3 years ago
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