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soldier1979 [14.2K]
3 years ago
6

How many kilograms are equivalent to 450 grams? I need step by step explanation please

Mathematics
1 answer:
Flauer [41]3 years ago
7 0

Step-by-step explanation:

0.45 kilograms. you decide the mass value by 1000.

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1. K + 8 > 19, if k = 11 is this a true statement
Ipatiy [6.2K]

Answer:

No, it isn't.  

Step-by-step explanation:

The correct statement would be K + 8 = 19  <<<<<<<<\

11 + 8 equals 19 not greater than 19.

4 0
3 years ago
Why is ti that when you add two numbers together (5+5,6+6,3+3, etc.) you get an even sum?? I need this for my 8 year-old-brother
astra-53 [7]

Essentially, the rule goes as so: odd + odd = even, even + even = even.

Although that may not be the answer you're looking for, it is a math rule that is never debunked and essentially the premises for why you get an even sum practically always depending on the numbers.

Hope this helps!

3 0
3 years ago
Read 2 more answers
Finding the surface area and volume to the nearest tenth
erastovalidia [21]
The cylinder:
pi x r^2 x h
= pi x 8^2 x 20
then times it by a half
= 2009.6
 The prism:
l x w
= 32 x 20
= 640
All up:
2009.6 +640
The shape equals 2649.6 cm sqaured
6 0
4 years ago
Need help quickly, please and thank you;
gulaghasi [49]
F(x) = y = -1/3x + 0
g(x) = y= -1/3x - 3

I don’t think that you have to include the y in the equations. It really depends on what your teacher wants. ;)

Hope this helps✨❤️
Merry Early Christmas!
3 0
3 years ago
1+secA/sec A = sin^2 A / 1-cos A​
Fofino [41]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}

\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}

\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}

\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}

\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}

\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark

3 0
4 years ago
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