Hello,
any point equidistant from the ends of a segment belongs to the perpendicular bisector of the segment.
|AD|=|BD| and |AC|=|BC|
Answer:
(-8/7 ; 5/7)
Step-by-step explanation:
5t + 1/2s = 3 - - - (1)
3t - 6s = 9 - - - - - (2)
Multiply (1) by 12 and (2) by 1
Add the result to eliminate s
60t + 6s = 36
3t - 6s = 9
____________
63t = 45
t = 45 / 63
t = 5/7
Put t = 5/7 in either (1) or (2) to obtain the value of s
3(5/7) - 6s = 9
15/7 - 6s = 9
-6s = 9 - 15/7
-6s = (63 - 15)/7
-6s = 48/7
s = 48/7 * - 1/6
s = - 8/7
Hello!
We could write this as an equation below.
0.76x=703
We divide both sides by 0.76.
x=925
Therefore, the regular price is $925.
I hope this helps!
Answer:
Step-by-step explanation:
Given: ∠N≅∠S, line l bisects TR at Q.
To prove: ΔNQT≅ΔSQR
Proof:
From ΔNQT and ΔSQR
It is given that:
∠N≅∠S (Given)
∠NQT≅∠SQR(Vertical opposite angles)
and TQ≅QR ( Definition of segment bisector)
Thus, by AAS rule,
ΔNQT≅ΔSQR
Hence proved.
Statement Reason
1. ∠N≅∠S given
2. ∠NQT≅∠SQR Vertical angles are congruent
3. line l bisects TR at Q. given
4. TQ≅QR Definition of segment bisector
5. ΔNQT≅ΔSQR AAS theorem
Hence proved.
Thus, option D is correct.
Answer:
2:45
Step-by-step explanation:
