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3 years ago

How do you find the arc length of the partial circle.

Mathematics

1 answer:

sesenic [268]3 years ago

6 0

Answer:

To find arc length, start by dividing the arc's central angle in degrees by 360. Then, multiply that number by the radius of the circle. Finally, multiply that number by 2 × pi to find the arc length i hope this helps!

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harkovskaia [24]

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What is the solution m<1?

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What is the slope of the linear equation below?

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2 years ago

Hey guys plz help meee<br><br>the answers have to be in numbers.

Licemer1 [7]

Answer:

$\overrightarrow{AB}=\frac{-9}{-4}$

$\overrightarrow{CD}=\frac{-5}{4}$

Step-by-step explanation:

A vector quantity is represented by $(\frac{y}{x})$

where y = y-coordinate and x = x-coordinate

Since vector AB represents a vector in 3rd quadrant,

It starts from point A and ends at B,

Therefore, coordinates of B are (-9, -4)

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3 years ago

what is the simplified form of the following expression? Assume X 0 and y 0. 2(^4 sqrt 16 x) -2(^4 sqrt 2y )+3 (^4 sqrt 81x ) -4

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For this case we have the following expression:

$2(\sqrt[4]{16x})-2(\sqrt[4]{2y})+3(\sqrt[4]{81x})-4(\sqrt[4]{32y})$

Rewriting the numbers within the roots we have:

$2(\sqrt[4]{2*2*2*2x})-2(\sqrt[4]{2y})+3(\sqrt[4]{3*3*3*3x})-4(\sqrt[4]{2*2*2*2*2y})$

Then, by properties of powers we have:

$2(\sqrt[4]{2^4x})-2(\sqrt[4]{2y})+3(\sqrt[4]{3^4x})-4(\sqrt[4]{2^42y})$

Then, by radical properties we have:

$2(2\sqrt[4]{x})-2(\sqrt[4]{2y})+3(3\sqrt[4]{x})-4(2\sqrt[4]{2y})$

Rewriting the expression we have:

$4\sqrt[4]{x}-2\sqrt[4]{2y}+9\sqrt[4]{x}-8\sqrt[4]{2y}$

Finally, adding similar terms we have:

$(4+9)\sqrt[4]{x}-(2+8)\sqrt[4]{2y}$

$13\sqrt[4]{x}-10\sqrt[4]{2y}$

Answer:

The simplified form of the expression is:

$13\sqrt[4]{x}-10\sqrt[4]{2y}$

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3 years ago

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