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irga5000 [103]
3 years ago
6

The incomes in a certain large population of college teachers have a Normal distribution, with mean $75,000 and standard deviati

on $10,000. Sixteen teachers are selected at random from this population to serve on a committee. What is the probability that their average salary is more than $77,500?
Mathematics
2 answers:
Natali [406]3 years ago
8 0

Answer:

probability that their average salary is more than $77,500 is 0.1587

Step-by-step explanation:

standard error

= 10,000/sqrt(16)

=10,000/4

= 2500 

(77,500 - 75000)/2500

2,500/2500

= 1 

p (z > 1) = .1587

So, the probability that their average salary is more than $77,500 is 0.1587

Marizza181 [45]3 years ago
6 0

Answer:

probability that their average salary is more than $77,500 is 0.1587

Step-by-step explanation:

If my answer qualifies please mark brainliest!

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Solve the equation 3sin2 theta = sin e, for values of e between Oº and 360°
Reil [10]

Answer:

[B] 0, 19.5, 160.5, 180, 360

Step-by-step explanation:

3 sin²θ = sin θ

3 sin²θ − sin θ = 0

sin θ (3 sin θ − 1) = 0

sin θ = 0 or sin θ = ⅓

If sin θ = 0, θ = 0°, 180°, 360°.

If sin θ = ⅓, θ = 19.5°, 160.5°.

5 0
3 years ago
What is the value of n in the diagram below?
IRINA_888 [86]

Answer:

n = 24

Step-by-step explanation:

(n + 18) and 2n are "complementary angles:"  they add up to 90°.

Thus, n + 18 + 2n = 90.  Combining the n terms results in 3n + 18 = 90.

Then 3n = 72.  Dividing both sides by 3 results in n = 24.

n is 24, so n + 18 is 42 and 2n is 48.  Note that 42 and 48 add up to 90.

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3 years ago
Am i missing any upgrades also what is half of 138
zhannawk [14.2K]

Answer:

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4 0
3 years ago
What is the area of a regular hexagon (6 sides) whose
Ganezh [65]

Step-by-step explanation:

With reference to the regular hexagon, from the image above we can see that it is formed by six triangles whose sides are two circle's radii and the hexagon's side. The angle of each of these triangles' vertex that is in the circle center is equal to 360∘6=60∘ and so must be the two other angles formed with the triangle's base to each one of the radii: so these triangles are equilateral.

The apothem divides equally each one of the equilateral triangles in two right triangles whose sides are circle's radius, apothem and half of the hexagon's side. Since the apothem forms a right angle with the hexagon's side and since the hexagon's side forms 60∘ with a circle's radius with an endpoint in common with the hexagon's side, we can determine the side in this fashion:

tan60∘=opposed cathetusadjacent cathetus => √3=Apothemside2 => side=(2√3)Apothem

As already mentioned the area of the regular hexagon is formed by the area of 6 equilateral triangles (for each of these triangle's the base is a hexagon's side and the apothem functions as height) or:

Shexagon=6⋅S△=6(base)(height)2=3(2√3)Apothem⋅Apothem=(6√3)(Apothem)2

=> Shexagon=6×62√3=216

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