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yanalaym [24]
3 years ago
13

Which statement is true about the equation fraction 3 over 4z = fraction 1 over 4z − 3 + 5?

Mathematics
2 answers:
sveticcg [70]3 years ago
7 0

Answer:

two solutions

Step-by-step explanation:

uranmaximum [27]3 years ago
3 0

Answer:

It has two solutions.

Step-by-step explanation:

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I need help solving this problem please
guapka [62]
Perimeter= 16
Area= 12
5 0
3 years ago
Solve for p, I don't know what else to add but yeah<br> solve for p?<br> Also explain
Charra [1.4K]

Answer:7

Step-by-step explanation:

6p-4+7p+3=90

13p-1=90

13p=91

p=7

4 0
3 years ago
Pls help tap picture to see the three problems
valentinak56 [21]
1. Slope intercept form. First find two points to get slope: (0,-3) and (-3,-4). Slope is
(-4 - -3)/(-3 - 0)= 1/3
Use one of the points of (x,y) to solve for b
Y=1/3x + b
-3 = 1/3(0) + b
-3 = b so your slope intercept equation is
Y = 1/3x - 3

2. Rate of Change is slope. Your points are (0,10) and (24,6) so slope is (6-10)/(24-0)
= - 1/6 which means that for each 1 unit increase in x, y decreases by 1/6.

3. Standard form is ax + by =c
Notice it is the same line as in the first graph so it's the same equation
y = 1/3x - 3
First, you cannot have fractions, so you have to multiply the equation by 3 to get rid of the 1/3.
3y= x - 9. Now move the x over:
-x + 3y = - 9. Now get rid of the negative value on x by multiplying the entire equation by -1:
x - 3y = 9
8 0
3 years ago
Which is greater 34.653 or 3.4653?
Charra [1.4K]
34 is larger than 3, so 34.653
4 0
3 years ago
Read 2 more answers
Please help me with this question!! I also need the steps
e-lub [12.9K]

Hi there!

\large\boxed{x = \frac{\pi}{3} \text{ and } \pi}

We are given:

cos(7x)cos(4x) = -1 - sin(7x)sin(4x)

Begin by moving all terms with variables to one side:

cos(7x)cos(4x) + sin(7x)sin(4x) = -1

The corresponding trig identity is cos(A - B). Thus:

cos(7x - 4x) = cos(7x)cos(4x) + sin(7x)sin(4x) = -1

cos(3x) = -1

cos = -1 at  π, so:

3x = π

x = π/3

We can also find another solution. Let 3π = -1:

3x = 3π

x = π

Thus, solutions on [0, 2π) are π/3 and π.

8 0
3 years ago
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